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3 years ago

Please give answer of 6 number

Mathematics

2 answers:

Irina18 [472]3 years ago

8 0

Answer:

$7,500$

Step-by-step explanation:

Let's solve this problem step-by-step. The library had 1,500 books in 2011. The ratio of books in 2011 and in 2012 is 1:2. Therefore, let the number of books in 2012 be $x$ .

We have the following proportion:

$\frac{1}{1,500}=\frac{2}{x},\\x=2\cdot 1,500=3,000$

Therefore, there were 3,000 books in 2012. The ratio of books in 2012 and in 2013 is 2:5. Let the number of books in 2013 be $y$ .

We have:

$\frac{2}{3,000}=\frac{5}{y},\\2y=5\cdot 3,000,\\2y=15,000\\y=\boxed{7,500}$

Therefore, there were 7,500 books in 2013.

Thepotemich [5.8K]3 years ago

6 0

Answer:

7,500 books

Step-by-step explanation:

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The total price of the car will be 26,400

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3 years ago

What is the answer 2+31×1/10+14×1/100

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Simplify the expression.

Exact Form is:
 $\frac{131}{25}$

The decimal form is:

5.24

Mixed Number Form is:

$5\frac{6}{25}$

4 0

3 years ago

Snow Dome Ski Resort has 75 inches of snow. It is currently snowing there at a rate of 1 inch per hour. Mt. Winterpark Ski Resor

Nastasia [14]

Answer:

a. See explanation for table

b. The 7th hour

Step-by-step explanation:

Given

Ski Resort

$Base\ Snow = 75in$

$Rate = 1in$ hourly

Mt. Winterpark

$Base\ Snow = 68in$

$Rate = 2in$ hourly

First, we need to illustrate the amount of snow as an equation in both cases.

$Amount = Base\ Snow + Rate * Time$

Let x be number of hours. and y be the amount of snow

So:

Ski Resort

$y= 75 + 1* x$

$y= 75 + x$

Mt. Winterpark

$y= 68 + 2 * x$

$y= 68 + 2x$

Next, we make a table to show the data.

When $x = 0$

Ski Resort: $y = 75 + 0 = 75$

Mt. Winterpark: $y = 68 + 2(0) = 68$

When $x = 1$

Ski Resort: $y = 75 + 1 = 76$

Mt. Winterpark: $y = 68 + 2(1) = 70$

When $x = 2$

Ski Resort: $y = 75 + 2 = 77$

Mt. Winterpark: $y = 68 + 2(2) = 72$

When $x = 3$

Ski Resort: $y = 75 + 3 = 78$

Mt. Winterpark: $y = 68 + 2(3) = 74$

When $x = 4$

Ski Resort: $y = 75 + 4 = 79$

Mt. Winterpark: $y = 68 + 2(4) = 76$

When $x = 5$

Ski Resort: $y = 75 + 5 = 80$

Mt. Winterpark: $y = 68 + 2(5) = 78$

When $x = 6$

Ski Resort: $y = 75 + 6 = 81$

Mt. Winterpark: $y = 68 + 2(6) = 80$

When $x = 7$

Ski Resort: $y = 75 + 7 = 82$

Mt. Winterpark: $y = 68 + 2(7) = 82$

When $x = 8$

Ski Resort: $y = 75 + 8 = 83$

Mt. Winterpark: $y = 68 + 2(8) = 84$

When $x = 9$

Ski Resort: $y = 75 + 9 = 84$

Mt. Winterpark: $y = 68 + 2(9) = 86$

When $x = 10$

Ski Resort: $y = 75 + 10 = 85$

Mt. Winterpark: $y = 68 + 2(10) = 88$

Hence, the table is:

x ---- Ski Resort ---- Mt. Winterpark

0 --------75 ----------- 68

1 --------76 ----------- 70

2 --------77 ----------- 72

3 --------78 ----------- 74

4 --------79 ----------- 76

5 --------80 ----------- 78

6 --------81 ----------- 80

7 --------82 ----------- 82

8 --------83 ----------- 84

9 --------84 ----------- 86

10 -------85 ----------- 88

(b)

From the table, the amount of snow is the same at the 7th hour and the snow is 82 inches

4 0

3 years ago

Evaluate the expression (25)=

natali 33 [55]

Answer:

?? im really confused sorry i dont think you finished the question

4 0

3 years ago

Read 2 more answers

Suppose integral subscript 3 superscript 5 f (x )space d x equals 5 integral subscript 3 superscript 9 g (x )space d x equals 3

igomit [66]

Answer:

Step-by-step explanation:

First we need to find the integral from 3 to 5 of g(x).

$\int\limits^9_3 {g(x)} \, dx =\int\limits^5_3 {g(x)} \, dx +\int\limits^9_5 {g(x)} \, dx \\\\\int\limits^5_3 {g(x)} \, dx =\int\limits^9_3 {g(x)} \, dx -\int\limits^9_5 {g(x)} \, dx\\\\\int\limits^5_3 {g(x)} \, dx =3-4=-1$

Then the integral of interest is ...

$\int\limits^5_3 {(f(x)+2g(x))} \, dx =\int\limits^5_3 {f(x)} \, dx +2\int\limits^5_3 {g(x)} \, dx =5+2(-1)\\\\\boxed{\int^5_3 {(f(x)+2g(x))} \, dx =3}$

6 0

3 years ago

Please give answer of 6 number​

Please give answer of 6 number