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3 years ago

What equivalency exists between solid volume and liquid volume

2 answers:

8 0

The main equivalency we can find that exists between the solid volume and liquid volume is that they both contain a definite volume. In addition, they are collectively called condensed phases due to the particles having virtual contact with each other.

polet [3.4K]3 years ago

7 0

Answer:

the answer is condensed phases I hope it will help you please follow me

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Please help me on questions 3 and 6, thank you! :D I'll give brainliest!

Anarel [89]

Answer:

3. if you increase your mass you also increase the gravitational pull

6. Radiant energy doesn't depend on a medium and sound energy is dependent on a medium.

Explanation:

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3 years ago

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A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the tra

Tatiana [17]

Answer:

The centripetal acceleration of the car is $8\ m/s^2$ .

Explanation:

Let the mass of the car, $m=10^3\ kg$

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(20\ m/s)^2}{50\ m}$

$a=8\ m/s^2$

So, the centripetal acceleration of the car is $8\ m/s^2$ . Hence, this is the required solution.

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4 years ago

Bádminton is played to a score of

Temka [501]

Badminton is played to a score of 21 points

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3 years ago

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A skater of mass 40 kg is carrying a box of mass 5 kg. The skater has a speed of 5 m/s with respect to the floor and is gliding

Yuki888 [10]

For the part a) we need only the momentum of the box and we have the data to find it.

Momentum is given by,

$p=mv$

where clearly, p is the momentum, m the mass of the box and v is the velocity.

Substituting,

$p=(5kg)(5m/s)\\p=25kg.m/s$

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

$p=(5kg)(5m/s)\\p=25kg.m/s$

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3 years ago

35. (II) A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging on a 2.8-m long string, which makes th

pentagon [3]

Answer:

Explanation:

Let mass of bullet = m1 = 28g= 0.028 kg

mass of pendulum = m2 = 3.1 kg

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3 years ago