Question

A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed 1.80 rad/s. Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises.

Answer 1

Answer:

$K.E = 0.1905 J$

Explanation:

From the question we are told that:

Length $L=1.4m$

Mass $m=180g$

Angular Velocity $\omega=1.80rads/s$

Generally the equation for Kinetic energy K.E is mathematically given by

 $K.E =0.5 (1/3 ML^2 )w^2$

 $K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2$

 $K.E = 0.1905 J$