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xz_007 [3.2K]
3 years ago
8

Why must the Ojibwe people pay close attention to the seasons?

Physics
1 answer:
sukhopar [10]3 years ago
4 0

Answer:C. They must know the right time of year for gathering certain foods

Explanation:

I got it correct

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A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling west at 20.0 m/s. The cars stick together. What is
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Answer:

17.27m/s

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M1U1 + M2U2 = (M1+M2)V

(900x15) + (750 x 20) = (900+750)V

13500+15000 = (1650)V

28500 = 1650v

V = 28500/1650 = 17.27m/s

V = 17.27m/s

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A bird sitting high in a tree is an example of an object with what type of energy?
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Which receptor is responsible for reporting light pressure and cold?
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If an object is moving and the forces acting on it are unbalanced in the direction of motion, the object will...
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(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
attashe74 [19]

Complete Question

(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?

(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?

The  tensile  strength of the nylon string is  600*10^{6} \  N/m^2

Answer:

A

   T = 471.3 \  N

B

 To prevent breakage the thickness of the string is increased

  String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Explanation:

From the question we are told that

     The  diameter is  d =  1.00 \ mm  =  0.001 \  m  

       The  tensile strength of the nylon string is \sigma =  600 *10^{6} \  N/m^2

  Generally the radius is mathematically evaluated as

     r=  \frac{d}{2}

=>    r =  \frac{0.001}{2}

=>     r =  0.0005 \  m

The cross sectional area is mathematically represented as

     A = \pi  r^2

=>   A =  3.142  *  (0.005)^2

=>    A =  7.855*10^{-7}\  m^2

Generally the tensile strength of nylon is mathematically represented as

      \sigma  = \frac{T}{ A }

Where T is the tension on the maximum tension on the string

 So  

           T =  \sigma  *  A

=>          T =  600*10^{6} *  7.855*10^{-7}

=>         T = 471.3 \  N

Form the equation above  we  see that

        T  \  \alpha \  A

So if the tension is  increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional  area )

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

8 0
4 years ago
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