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3 years ago

7

What is the length of the base of a right triangle with an area of 15 square meters and a height of 3 meters? A. 5 m B. 10 m C.

30 m D. 45 m

1 answer:

Rzqust [24]3 years ago

4 0

Answer:

B.10

Step-by-step explanation:

15=1/2b(3)

30=3b

10= base

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2/0 = 32/48 = 30/0. What number shpuld come in place of the zeros?

Anton [14]

Answer:

$\sf \dfrac{2}{3} = \dfrac{32}{48} = \dfrac{30}{45}$

<h3><u>For the 1st part</u></h3>

$\sf \rightarrow \dfrac{2}{x} = \dfrac{32}{48}$

$\sf \rightarrow 2(48)= {32x}$

$\sf \rightarrow 32x= 96$

$\sf \rightarrow x = 3$

<h3><u>For the 2nd part</u></h3>

<u /> $\rightarrow \sf \dfrac{32}{48} = \dfrac{30}{y}$

$\rightarrow \sf {32y} = 30(48)$

$\rightarrow \sf {32y} = 1440$

$\rightarrow \sf y = 45$

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TEA [102]

Answer:

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Step-by-step explanation:

divide 30 by 5 to get the value of d

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What is the surface area of the cone? Express your answer in terms of π.b

weeeeeb [17]

Given:

Radius of the cone = 5 ft

Slant height of the cone = 21 ft

To find:

The surface area of the cone

Solution:

Surface area of cone formula:

$SA=\pi r^{2}+\pi r l$

where r is the radius and l is the slant height.

$SA=\pi \times 5^{2}+\pi \times 5 \times 21$

$SA=\pi \times 25+\pi \times 105$

$SA=25 \pi+ 105 \pi$

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The surface area of the cone is 130π square feet.

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