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Westkost [7]
3 years ago
9

The answer please for my online class

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

B. -500

Step-by-step explanation:

\dfrac{(2a^4)^2}{a^0a^5} =

= \dfrac{2^2a^8}{a^5}

= 4a^3

= 4(-5)^3

= 4(-125)

= -500

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Please answer the question, I think I have the answer but I'm not sure.
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3 years ago
Determine if 3√10 /4 is in simplest form. if the expression is not in simplest form explain why? HELP PLEASE
emmasim [6.3K]

The notation in its current form isn't entirely clear.

Did you mean to write \frac{3\sqrt{10}}{4}? The 4 isn't in the square root.

If so, then the expression is in simplest form because we cannot simplify \sqrt{10} any further (note how 10 doesn't have any perfect square factors other than 1).

Also, the 3/4 portion is fully reduced already.

------------------------

Or,

Did you mean to write 3\sqrt{\frac{10}{4}} ? This time the 4 is inside the square root.

If so, then we can simplify like this

3\sqrt{\frac{10}{4}}\\\\\frac{3\sqrt{10}}{\sqrt{4}}\\\\\frac{3\sqrt{10}}{2}\\\\

This means that 3\sqrt{\frac{10}{4}}=\frac{3\sqrt{10}}{2}\\\\

7 0
3 years ago
How many zeros are there in the standard form of six hundred thousand, twenty?
Julli [10]
There are Three zeros

3 0
3 years ago
Which solution to the equation 1/x-1 = x-2/2x^2-2 is extraneous
melamori03 [73]

<u>Solution-</u>

The equation given here,

\frac{1}{x-1} =\frac{x-2}{2x^2-2}

\Rightarrow 2x^2-2=(x-1)(x-2)

\Rightarrow 2x^2-2=x^2-3x+2

\Rightarrow x^2+3x-4=0

\Rightarrow x^2 +4x-x-4=0

\Rightarrow (x-1)(x+4)=0

\Rightarrow x=1 \ and -4

But, at x=1, \frac{1}{x-1} \ and \ \frac{x-2}{2x^2-2} becomes infinity so it can't be a solution to the equation.

∴ x=1 is the extraneous solution of the equation

3 0
3 years ago
Read 2 more answers
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