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2 years ago

I need help plz i will mark you brainlest

Mathematics

1 answer:

Dovator [93]2 years ago

8 0

Answer:

$\frac{7}{4} - \frac{3}{4} = \frac{4}{4}$

Step-by-step explanation:

To find the number midway between 3/2 and 4/2, add them up and divide by 2

we have, 3/2 + 4/2 = 7/2

7/2 ÷ 2 = 7/4

Repeat the same for the number midway between 1/2 and 2/2 to get 3/4

The answer then is, 7/4 - 3/4 = 4/4

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Solve for a. 2z=4a/m +3

Finger [1]

Answer:

Step-by-step explanation:

2z = 4a/m +3

-3 -3

2z - 3 = 4a/m

×m ×m

(2z -3)m = 4a

÷4 ÷4

[(2z -3)m]/4 = a

a = (2mz - 3m)/4

4 0

3 years ago

Steve jobs sells apples and gets paid on a graduated commission scale. He gets 4% of the first $1000 and 6% of anything over $10

GREYUIT [131]

Answer:

Step-by-step explanation:

1000*4%= 40

10000*6%=600

640

7 0

2 years ago

Read 2 more answers

Classify each number below as an integer or not.

pshichka [43]

Answer:

yes, no, no, yes, yes

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

HELP ME WITH 61 <br>I'm freaking out!!!!!!!!!!!!<br>I don't know what to do

Brut [27]

4.25+1.25*m, 5.75+0.75*m
4.25+5.75=10 and 1.25+0.75 = 2 therefore the two expressions are 2m+10
0.5m-1.5 : 4.25+1.25+m-5.75+0.75*m =0.5m-1.5 ( I'm quite sure about this one but I can't think of another answer but this )

5 0

2 years ago

Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%

balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

$A=A_{o}e^{-0.0001211.t}$ (1)

Where:

$A$ is the final amount of Carbon- 14

$A_{o}=$ is the initial amount of Carbon- 14

$t$ is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 $A$ is $19\%=0.19$ , assuming the initial amount of Carbon-14 $A_{o}=$ is $100\%$ :

$A=0.19A_{o}$ (2)

This means: $\frac{A}{A_{o}}=0.19$ (2)

Now,finding $t$ from (1):

$\frac{A}{A_{o}}=e^{-0.0001211.t}$ (3)

Applying natural logarithm on both sides:

$ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})$ (4)

$ln(0.19)=-0.0001211.t$ (5)

$t=\frac{ln(0.19)}{-0.0001211}$ (6)

Finally:

$t=13713.717years$ This is the age of the paintings and the option that is nearest to this value is C. 13839 years

6 0

2 years ago