What is the question?
Matt sold 8 tickets at $9 each. 8 tickets x $9= $72
He still has 6 tickets left. 6 x $9=$54
Total tickets=14
Total amount of money when he is done selling the rest of the tickets is $126
-x+4y=8: Parallel
4x+y=-1: Perpendicular
y=-1/4x+6: neither
y=-4x-3: Perpendicular
The interquartile range is 24.5
the variability is 69
9x-10=5x+38
4x=48
X=12
So 9x-10=9(12)-10=108-10=98 degrees
And 5x+38=5(12)+38=60+38=98 degrees
<span>At
the restaurant you only have $30 to spend on dinner.
=> 8% sales tax is applied in your bill.
=> And need to leave a 20% tip.
Now, let’s find out how much will be the most expensive item you can order
Let us solve for the 8% tax first
=> 30 dollars * 8%
=> 30 dollars *.08 = 2.4 dollars
Then let’s solve the 20% tip
=> 30 dollars * .20 = 6 dollars
Solve
=> 2.4 + 6.00 = 8.4 dollars
=> 30 dollars – 8.4 dollars = 21.6 dollars
Thus, you can only spend around 22 dollars to be able not to exceed at your 30
dollars budget.
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