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3 years ago

6

Which statement describes the expression below? 1 + 6 ÷ 2 × 3 Multiply the quotient of 6 and 2 by 3, then add 1. Add 1 and 6, th

en divide by 2 and multiply by 3. Divide 6 by the product of 2 and 3, then add 1. Add 3 to half of 6 multiplied by 1.

1 answer:

son4ous [18]3 years ago

5 0

Answer:

Add 1 and 6, then divide by 2 and multiply by 3.

Step-by-step explanation:

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Round 292,831 to the ten-thousands place.

Nadusha1986 [10]

Answer:

the answer is 290000

Step-by-step explanation:

8 0

3 years ago

How to find the square root in long division method for 5.4289

sladkih [1.3K]

<h2>The Square root of 5.4289 is 2.33</h2>

(explanation attached)

6 0

2 years ago

A stock market analyst notices that in a certain year, the price of IBM stock increased on 131 out of 252 trading days. Can thes

san4es73 [151]

Answer:

95% confidence interval for the proportion of days that IBM stock increases.

(0.45814 , 0.58146)

Step-by-step explanation:

<u><em>Step:1</em></u>

Given that a stock market analyst notices that in a certain year, the price of IBM stock increased on 131 out of 252 trading days.

Given that the sample proportion

$p^{-} = \frac{131}{252} = 0.5198$

Level of significance = 0.05

Z₀.₀₅ = 1.96

<u><em>Step:2</em></u>

<u><em>95% confidence interval for the proportion of days that IBM stock increases.</em></u>

<u><em></em></u> $(p^{-} - Z_{0.05} \frac{\sqrt{p(1-p)} }{\sqrt{n} } , p^{-} + Z_{0.05} \frac{\sqrt{p(1-p)} }{\sqrt{n} } )$ <u><em></em></u>

$(0.5198 - 1.96(\sqrt{\frac{0.5198(1-0.5198)}{252} } , 0.5198 +1.96(\sqrt{\frac{0.5198(1-0.5198)}{252} })$

(0.5198 - 0.06166 , 0.5198+0.06166)

(0.45814 , 0.58146)

<u><em>Final answer:-</em></u>

95% confidence interval for the proportion of days that IBM stock increases.

(0.45814 , 0.58146)

3 0

3 years ago

A cone and a cylinder have the same base and height, as shown below.

marshall27 [118]

The statement that apply is that the volume of the cone is One-third the volume of the cylinder

<h3>How to find the volume of a cone and cylinder?</h3>

volume of a cone = 1 / 3 πr²h

where

r = radius
h = height of the cone

Volume of a cylinder = πr²h

where

r = radius
h = height

The cone and the cylinder has the same base and height. Therefore, the radius and height are the same .

volume of the cylinder = 84π

Therefore, the volume of the cone is One-third the volume of the cylinder.

learn more on volume here: brainly.com/question/16031618

#SPJ1

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2 years ago

The amount of coffee that a filling machine puts into an 8 dash ounce 8-ounce jar is normally distributed with a mean of 8.2 oun

Inessa [10]

Answer:

73.3% probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100 jars, will be at most 0.02 ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theore.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018$

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100 jars, will be at most 0.02 ounce

That is, probability of the sample mean between 8.2-0.02 = 8.18 and 8.2 + 0.02 = 8.22, which is the pvalue of Z when X = 8.22 subtracted by the pvalue of Z when X = 8.18.

X = 8.22

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.22 - 8.2}{0.018}$

$Z = 1.11$

$Z = 1.11$ has a pvalue of 0.8665.

X = 8.18

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.18 - 8.2}{0.018}$

$Z = -1.11$

$Z = -1.11$ has a pvalue of 0.1335.

0.8665 - 0.1335 = 0.7330

73.3% probability that the sampling error made in estimating the mean amount of coffee for all 8 dash ounce 8-ounce jars by the mean of a random sample of 100 jars, will be at most 0.02 ounce

6 0

3 years ago