The product of the given two matrices comes out to be ![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Here we are given the 2 matrices as follows-
![\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-2%5C%5C-6%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C3%263.5%5Cend%7Barray%7D%5Cright%5D)
To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.
Here since both of the matrices are 2 × 2, their product is possible.
Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.
Therefore,
![\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%287%2A1%29%2B%28-2%2A3%29%26%287%2A1%29%2B%28-2%2A3.5%29%5C%5C%28-6%2A1%29%2B%282%2A3%29%26%28-6%2A1%29%2B%282%2A3.5%29%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%287%29%2B%28-6%29%26%287%29%2B%28-7%29%5C%5C%28-6%29%2B%286%29%26%28-6%29%2B%287%29%5Cend%7Barray%7D%5Cright%5D)
=
Thus, the product of the given two matrices comes out to be
Learn more about matrices here-
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Answer:
A) x + 0
Step-by-step explanation:
In triangle ABC, the coordinates are: A(1, -1), B(1, -5) and C(4, -5)
In triangle A'B'C', the coordinates are: A(1, -5), B(1, 1) and C(4, 1)
Look at the x-coordinates in both the triangles remains the same because the triangles are reflected over x-axis, therefore, only the y-coordinate changes.
Therefore, the rule for x-coordinates = x + 0
Answer: A) x + 0
Hope this will helpful.
Thank you.
I got 45.... u might want to check first
Answer:
TRUE If substituting the test point produces a false solution, we shade on the opposite side of the line.
FALSE Elimination will give you an exact answer to a system of equations.
Step-by-step explanation:
Weird, I thought I already answer this xD
