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3 years ago

Solve for x. Round to the nearest tenth, if necessary.

Mathematics

2 answers:

blsea [12.9K]3 years ago

6 0

Answer:

ST = x = 1.8 (to the nearest tenth)

Step-by-step explanation:

STU is a right triangle right angled at T with S =61° and hypotenuse SU=3.7 units.

ST = x = SUcos(61°) = 3.7cos(61°) = 3.7*0.48481 = 1.7938

Over [174]3 years ago

5 0

Answer:

The answer is 1.8

Step-by-step explanation:

soh-cah-toa trigonometry. Cos 61=x/3.7. Isolate the variable. 3.7cos61=x. Solve for x. X= 1.793795595 (rounded to the nearest tenth the answer is 1.8)

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X over 3 is less then or equal to 5

Trava [24]

Answer:

x/3 ≤ 5

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There are approximately 4.3 weeks in each month. How much will you take home each month after taxes?

Marianna [84]

Answer:

So roughly c x c = b/100

5 x 5 x 100 = $2500

Step-by-step explanation:

Lets say c = 5 and b = 1

= 5c =100c/5c x b

= 20c x b

We can also show

= 20c x b =5c

c = 20c/5c x b = 5c

1/20 x 5c = 5c

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One example is 20% = 0.20 x 500 = 100c

= 7.12c = 7c

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710-107 = 603 a week

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4 0

3 years ago

Y=4x-6 and passes through point 8,12

umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

$y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20$

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

$y=mx+b\\y=4x-20$

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

$y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14$

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

$y=mx+b\\y=-\frac{1}{4} x+14$

8 0

2 years ago

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allsm [11]

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