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3 years ago

Solve for x. Round to the nearest tenth, if necessary.

Mathematics

2 answers:

blsea [12.9K]3 years ago

6 0

Answer:

ST = x = 1.8 (to the nearest tenth)

Step-by-step explanation:

STU is a right triangle right angled at T with S =61° and hypotenuse SU=3.7 units.

ST = x = SUcos(61°) = 3.7cos(61°) = 3.7*0.48481 = 1.7938

Over [174]3 years ago

5 0

Answer:

The answer is 1.8

Step-by-step explanation:

soh-cah-toa trigonometry. Cos 61=x/3.7. Isolate the variable. 3.7cos61=x. Solve for x. X= 1.793795595 (rounded to the nearest tenth the answer is 1.8)

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$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

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Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

$y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o}$ (1)

Where:

$\Delta y$ - Amplitude.

$\omega$ - Angular frequency.

$x_{o}$ - Phase shift.

$y_{o}$ - Vertical shift.

$x$ - Independent variable.

$y$ - Dependent variable.

In addition, we know that the period associated with the sinusoidal function ( $T$ ) is:

$T = \frac{2\pi}{\omega}$

By direct comparison, we get the following conclusions:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

$y_{o} = D$ (Vertical shift) (Correct answer: 4)

$\frac{2\pi}{\omega} = \frac{2\pi}{B}$ (Period) (Correct answer: 5)

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