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2 years ago

Jennifer spent $42 on a magazine and 7 candy bars. The magazine cost $7, then how much was each candy bar

1 answer:

3 0

$5. You subtract the $7 from the $42 since that was the magazine then you divide that(35) by 7 since that is the amount of candy bars that were bought. That’ll give you the answer of $5 for each candy bar.

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There is one error in one of five blocks of a program. To find the error, we test three randomly selected blocks. Let X be the n

marusya05 [52]

Probability(error in one block)= 1/5
<span>Probability(error in 3 blocks)= 3*(1/5)= 0.6</span>

Let,
0 = No error
<span> 1 = error
</span>Hence.
E(x) = 0.4 x 0 x+0.6 + 1
= 1.6

6 0

2 years ago

Read 2 more answers

What was Miguel's mistake if any?

iogann1982 [59]

Answer:

Step-by-step explanation:

According to my answer, he shound have computed 2^3 which is 8 and suibstract that from four getting four, then multiplying it by tow to get eight so it should be 4 so Miguel made no mistakes.Since he was doing the order of operations for each step of the equation.

7 0

2 years ago

Read 2 more answers

Plzzz help me with this I’ll give brainliest

scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-(-1)}{(-4)-(-4)}$

m= $\frac{7}{0}$

The slope is 90 degree

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-6}{(-4)-(-1)}$

m= $\frac{0}{(-3)}$

The slope is zero degree

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-4)-6}{2-2}$

m= $\frac{-10}{0}$

The slope is 90 degree

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-(-4)}{(-4)-(2)}$

m= $\frac{3}{-6}$

m= $\frac{-1}{2}$

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{2-3}{3-(-2)}$

m= $\frac{-1}{5}$

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-2}{2-3}$

m= $\frac{-3}{-1}$

m=3

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{0-(-1)}{(-3)-2}$

m= $\frac{-1}{5}$

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{3-0}{(-2)-(-3)}$

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0

3 years ago

What is 1.9961 x 10^-7

kakasveta [241]

Answer:0.00000019961

Step-by-step explanation:

I moved the decimal place by the number of the exponent

4 0

3 years ago

Three ballet dancers are positioned on stage. Elizabeth is straight behind Hannah and directly left of Manuel. If Hannah and Eli

ki77a [65]

Answer: Elizabeth and Manuel have a distance of 4 meters between them.

Step-by-step explanation: Please refer to the picture attached.

From the information given, Elizabeth is directly behind Hannah and directly left of Manuel. That means we have three points which are HEM, that is, we now have triangle HEM. The longest side (hypotenuse) which is the distance between Hannah and Manuel is given as 5 meters while the other side the distance between Hannah and Elizabeth is given as 3 meters.

We shall apply the pythagoras theorem in solving for the unknown side, EM.

The Pythagoras theorem states thus;

AC² = AB² + BC²

Where AC is the hypotenuse, and AB and BC are the other two sides.

Substituting for the known values, we now have;

5² = 3² + EM²

25 = 9 + EM²

Subtract 9 from both sides of the equation

16 = EM²

Add the square root sign to both sides of the equation

√16 = √EM²

4 = EM

Therefore the distance between Elizabeth and Manuel is 4 meters

8 0

2 years ago

Jennifer spent $42 on a magazine and 7 candy bars. The magazine cost $7, then how much was each candy bar​

Jennifer spent $42 on a magazine and 7 candy bars. The magazine cost $7, then how much was each candy bar