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saw5 [17]
3 years ago
15

AD and ac are opposite rays. True False

Mathematics
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

False

Step-by-step explanation:

For AD and AC to be opposite rays they must be on the same straight line in opposite directions.

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Rex weighed 80 pounds a year ago. Now he weighs 92 pounds. What is the percent increase in his weight?
bezimeni [28]
So base on the question, that states the weight of Rex from last year to the present, and find its rate if change or percentage of change. To calculate the percentage you must first subtract the said weight in the present to its past then divide it by its past weight then multiply it by 100. So the percentage would be 15 %. I hope this would help 

8 0
3 years ago
HELP PLS IM FAILING PYTHAGOREAN THEOREM
Bond [772]

Answer: 4.6 km

Step-by-step explanation:

a^1 + b^2 = c^2

2^2 + b^2 = 5^2

4 + b^2 = 25

b = sqrt 25 - 4

b = sqrt 21 = 4.6 km

4 0
3 years ago
Read 2 more answers
Seanna Lives 5/8 mile from school. Haresh lives 1/3 mile from school. How much farther away from school does Seanna live than Ha
lidiya [134]
To answer you get the same denominator so multiply both denominators with each other and do the same with the top so 25 will be at both bottoms and well 15/25 and 8/25. Then solve
4 0
3 years ago
Y+23=59<br><br>solve for y i dont know if i have to add or subtract the 23 and 59
neonofarm [45]
When you move a number to the opposite side of the equation, in this occasion it will be 23- it changes to the opposite value. So us 23 is a positive value you can move it and change it to a negative. Or in other words suntract -23 from all sides of the equation, which will be equal to: 
y = 59 - 23
Y = 36

7 0
3 years ago
While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at
tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) =  speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)

simplifying the equation, we get

23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)

23(2.8+2.8)/29=2.8^2-x^2

x^2=(2.8)^2-(23*5.6)/29)=3.4

x=\sqrt{3.4}=1.84m/s

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

4 0
1 year ago
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