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snow_lady [41]
3 years ago
10

Side1 : 3x^2 − 4x − 1 (^to the second power)

Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

9514 1404 393

Answer:

  A. 2x^2 +4

  B. 5x^3 -4x^2 +3x -12

  C. addition and subtraction of polynomials result in polynomials (closed)

Step-by-step explanation:

A. The total of the two side lengths is ...

  (3x^2 -4x -1) +(-x^2 +4x +5) = (3 -1)x^2 +(-4+4)x +(-1+5) = 2x^2 +4

__

B. The length of the third side is the difference between the total for all three sides and the total for the given two sides:

  (5x^3 -2x^2 +3x -8) - (2x^2 +4) = 5x^3 +(-2-2)x^2 +3x +(-8-4)

  = 5x^3 -4x^2 +3x -12

__

C. Addition of the two polynomials results in a polynomial. Subtraction of the two polynomials results in a polynomial. There is nothing here to indicate the set of polynomials is not closed under addition and subtraction.

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What is the pattern between 1/4, 1/2, 3/4, and 1
bagirrra123 [75]

Answer:

Adding 1/4 each time

Step-by-step explanation:

1/4+1/4=1/2

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4 0
3 years ago
Meaghan and Lily are dividing 43.61 by 7. Meaghan says that the first digit of the quotient is in the ones place. Lily says it i
Ivahew [28]

Answer: Meaghan is right.

Step-by-step explanation:

For a number like:

123.45

the tens place would be the "2" (second number at the left of the decimal point)

The ones place would be the "3" (first number at the left of the decimal point)

Let's suppose that Lily is correct.

Then the quotient of:

43.61/7

Will be a number with two digits in the left of the decimal point.

The smallest number that meets this condition, is the number 10.

Then let's see:

7*10 = 70

then:

70/7 = 10

and:

43.61 < 70

(70 is larger than 43.61)

then:

43.61/7 < 70/7 = 10

Then:

(43.61/7) < 10

This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.

Then Meaghan is the correct one.

We also could perform the quotient to find:

43.61/7 = 6.23

So yes, Meaghan is correct.

5 0
3 years ago
If f(x-3)=x^2-4x+5, what's f(1-x)​
olganol [36]

Answer:

\large\boxed{f(1-x)=x^2-4x+5}

Step-by-step explanation:

f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2

f(1-x)=1^2-2(1)(x)+x^2+(2)(1)+(2)(-x)+2\\f(1-x)=1-2x+x^2+2-2x+2\qquad\text{combine like terms}\\f(1-x)=x^2+(-2x-2x)+(1+2+2)\\f(1-x)=x^2-4x+5

4 0
3 years ago
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