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snow_lady [41]
3 years ago
10

Side1 : 3x^2 − 4x − 1 (^to the second power)

Mathematics
1 answer:
Colt1911 [192]3 years ago
7 0

9514 1404 393

Answer:

  A. 2x^2 +4

  B. 5x^3 -4x^2 +3x -12

  C. addition and subtraction of polynomials result in polynomials (closed)

Step-by-step explanation:

A. The total of the two side lengths is ...

  (3x^2 -4x -1) +(-x^2 +4x +5) = (3 -1)x^2 +(-4+4)x +(-1+5) = 2x^2 +4

__

B. The length of the third side is the difference between the total for all three sides and the total for the given two sides:

  (5x^3 -2x^2 +3x -8) - (2x^2 +4) = 5x^3 +(-2-2)x^2 +3x +(-8-4)

  = 5x^3 -4x^2 +3x -12

__

C. Addition of the two polynomials results in a polynomial. Subtraction of the two polynomials results in a polynomial. There is nothing here to indicate the set of polynomials is not closed under addition and subtraction.

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\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

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