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meriva
3 years ago
11

Domain and range? Typically I understand domain and range but these graphs are vague in detail. If someone could help that'd be

great

Mathematics
1 answer:
brilliants [131]3 years ago
6 0
What do you mean? Oh oh oh I used to do this, what grade you it?
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What 2D shape can be created by slicing a cone vertically?
Triss [41]

Answer:

C) triangle

Step-by-step explanation:

Honestly I have no clue how to explain slicing shapes. but basically if a cone was a 2-D figure what shape would it be? a triangle

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2 years ago
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How can the Pythagorean Identity be used to find sin θ, cos θ, or tan θ and the quadrant location of the angle?
Archy [21]

First lets see the pythagorean identities

sin^2 \Theta + cos^2 \Theta =1

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

sin^2 \Theta = 1-cos^2 \Theta => sin \theta = \pm \sqrt{1-cos^2 \Theta}

Now we need to check the sign of sin theta

First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.

So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .

5 0
3 years ago
Find c.<br> Round to the nearest tenth:<br> 2 cm<br> 15°<br> 105
Anit [1.1K]

Answer:

0.5cm

Step-by-step explanation:

Using the sine rule

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Solve -6 - 4(-3) - 2 + 1 a.6 b.3 c.-3 d.-6​
Murljashka [212]

Answer:

Answer 5

Step-by-step explanation:

-6+12-2+1

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2 years ago
Identify all factors of the expression 12x^2-14x-6
Evgen [1.6K]

Let's solve this by using the quadratic formula:

\frac{-b+-\sqrt{b^2-4ac} }{2a}


Note that we only use the coefficients so a=12, b=-14, and c=-6.

Plug values in the quadratic equation:

\frac{ -  ( - 14)± \sqrt{ {( - 14)}^{2} - 4(12)( - 6) } }{2(12)}

And so by evaluating those values we obtain:

\frac{14+-\sqrt{484} }{24}=\frac{14+-22}{24}  \\\\

Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

\frac{14+22}{24}=\frac{36}{24}=\frac{3}{2}


Second Factor:

\frac{14-22}{24}=\frac{-8}{24}=-\frac{1}{3}


And so your factors are

\frac{3}{2},-\frac{1}{3}

meaning that those are your roots/x-intercepts.


6 0
3 years ago
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