Answer:
120 units
Step-by-step explanation:
Um -1/3(24+3)-1 = -10
So -10 is the answer
The length and width of the rectangle is 11 in and 8 in respectively.
Step-by-step explanation:
Given,
The width of a rectangle is 3 in less than the length.
The area of each congruent right angle triangle = 44 in²
To find the length and width of the rectangle.
Formula
The area of a triangle with b base and h as height =
bh
Now,
Let, the width = x and the length = x+3.
Here, for the triangle, width will be its base and length will be its height.
According to the problem,
×(x+3)×x = 44
or, 
or,
or,
+(11-8)x-88 = 0
or,
+11x-8x-88 =0
or, x(x+11)-8(x+11) = 0
or, (x+11)(x-8) = 0
So, x = 8 ( x≠-11, the length or width could no be negative)
Hence,
Width = 8 in and length = 8+3 = 11 in
By analyzing and understanding the graph of the absolute value function, we find that the function evaluated at the x-value equal to 1 is equal to the y-value equal to 3.
<h3>What is the y-value associated to a given x-value of an absolute value function? </h3>
In this problem we find the representation of an absolute value function, where the horizontal axis corresponds to the values of the domain, whereas the vertical axis is for the values of the range. In that picture we must look up for the y-value associated with a given x-value.
Then, we proceed to evaluate the absolute value function at x = 1. In accordance with the graph, the y-value , that is, from the vertical axis, associated with the x-value, that is, from the horizontal axis, equal to 1 is equal to a value of 3.
To learn more on absolute values: brainly.com/question/1301718
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Answer:
8,5 feet
Step-by-step explanation:
The equation of the form
x² + y² = (r)²
Is the equation of the circumference
We have for the pool:
x² + y² = 2500 ⇒ x² + y² = (50)²
And for the outside edge of the footpath
x² + y² = 3422,25 ⇒ x² + y² = (58,5)²
So we obtain the radius of each circumference
For the outside edge of the pool r₁ = 50 feet
For the outside edge of the footpath r₂ = 58,5 feet
Then the width of the footpath is 58,5 - 50 = 8,5 feet