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Paha777 [63]
3 years ago
5

Higher Order Thinking You have two different

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

18×12.00=$216.00

27×27.00=$729.00

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Find the general term of the sequence<br>c.1 { 10, 5, 0, -5, -10 }<br>c.2 { 1, 4, 9, 16, 25 }​
Ivan

Answer:

1. 15 - 5n where n>=1

2. n² where n>=1

Step-by-step explanation:

1. {10, 5, 0, -5, -10} is an Arithmetic Progression

nth term is a + (n - 1)d

where a = first term, n= nth term, d= common difference.

a = 10, d = -5 (5-10, 0-5, -5-0, -10-(-5))

Therefore, nth(General) term of the sequence:

= 10 + (n - 1)-5

= 10 + (-5n) + 5

= 10 + 5 - 5n

= 15 - 5n

Test:

if n = 1; 15 - 5(1) = 10

if n = 2; 15 - 5(2) = 5

if n = 3; 15 - 5(3) = 0 and so on.

2. {1, 4, 9, 16, 25}

The general term of the sequence is n²

Test:

if n = 1; 1² = 1

if n = 2; 2² = 4

if n = 3; 3² = 9 and so on.

5 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
2(v + 1). Simplify the expression
serg [7]

Answer:

2v+2

Step-by-step explanation:

8 0
2 years ago
a car travels 32 km due north and then 46 km in a direction 40 degress west of north. find the magnitude of the cars resultant v
kvv77 [185]

Answer:

50 degrees

Step-by-step explanation:

PLZ MARK BRAINLIEST

5 0
3 years ago
Pablo is a technical writer who works 7.5 hours per day. He spends twice as much time on writing tasks as he does on other work
NikAS [45]
Pablo spends 15 hours on writing tasks
answer: twice as much=2 times this number
then twice as much= 7.5 times 2
7.5 times 2= 15hrs
6 0
3 years ago
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