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uranmaximum [27]
3 years ago
10

The hands of a clock show the time 12:25 what kind of angle exists between the hands od the clock

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

Obtuse Angle

Hope this helps :)

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Determine whether the equation 2x + y = 8 is linear. If so, graph the function.
zepelin [54]

It is linear because both variables have an exponent of 1. (FYI: one of the exponents can be 0 and still be a linear equation).

2x + y = 8

<u>-2x     </u> <u> -2x</u>

      y = -2x + 8   ⇒ slope (m) = -2 and y-intercept (b) = 8

plot the y-intercept (0, 8). then plot the next point by counting the rise over run from the y-intercept. <em>count 2 units down and 1 unit to the right </em>= (1, 6).

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3 years ago
Find the area of the shaded region.Help ASAP!
alexira [117]

If you're talking about the red shaded part, the answer is 8

3 0
3 years ago
Choose the graph of y = –3x – 1
aleksley [76]

Answer:

Slope is -3

The x intercept is (0,-1)

The intercept is (- 1/3, 0)

6 0
3 years ago
Read 2 more answers
Hallie bikes 1 5/8 km before lunch 6 1/4 km How much farther does hallies bike after lunch than before lunch? Express your answe
kondaur [170]

Distance biked before lunch = 1\frac{5}{8} km (the number is written in mixed fraction)

⇒ Distance biked before lunch = \frac{13}{8}

Distance biked after lunch = 6\frac{1}{4} km (the number is written in mixed fraction)

⇒ Distance biked after lunch = \frac{25}{4}

We need to determine how much farther does Hallie bike after lunch than before lunch

Extra distance biked after lunch vs. before lunch = \frac{25}{4} - \frac{13}{8}

⇒ Extra distance biked after lunch vs. before lunch = \frac{50-13}{8}

⇒ Extra distance biked after lunch vs. before lunch = \frac{37}{8}

⇒ Extra distance biked after lunch vs. before lunch = 4\frac{5}{8} (in mixed fraction)

Hence, Hallie biked 4\frac{5}{8} km extra after lunch vs. before lunch.

3 0
3 years ago
The total cost (c) in dollars of renting a car for n days is given by the inequality LaTeX: c\ge125+50nc ≥ 125 + 50 n. What is t
zysi [14]

Answer:

<h3>6 days</h3>

Step-by-step explanation:

Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n

To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n

425 ≥ 125 + 50n

Subtract 125 from both sides

425 - 125 ≥ 125 + 50n  - 125

300≥ 50n

Divide both sides by 50

300/50≥50n/50

6 ≥n

Rearrange

n≤6

<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>

<em></em>

5 0
3 years ago
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