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uranmaximum [27]
3 years ago
10

The hands of a clock show the time 12:25 what kind of angle exists between the hands od the clock

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

Obtuse Angle

Hope this helps :)

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Solving proportion 10\8=n\10
Zanzabum
\frac { 10 }{ 8 } =\frac { n }{ 10 } \\ \\ 10\cdot \frac { 10 }{ 8 } =\frac { n }{ 10 } \cdot 10\\ \\ \frac { 100 }{ 8 } =n

\\ \\ n=\frac { 4\cdot 25 }{ 4\cdot 2 } \\ \\ \therefore \quad n=\frac { 25 }{ 2 }
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What the the answer to 36 = 18x
Feliz [49]

Answer:

Step-by-step explanation:

C=2

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the function f(x) = 3,005(1+0.03)^x represents the amount of money in a savings account where x represents time in years. what d
Stolb23 [73]

Answer:

Option d. the initial amount of money placed in the savings account

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we have

f(x)=3,005(1+0.03)^{x}

This is a exponential function of the form

f(x)=a(1+r)^{x}

where

a is the initial value

r is the growth rate

(1+r) is the base

x is the number of years

f(x) is the amount of money in a savings account

In this problem we have

a=$3,005

r=0.03=3%

(1+r)=1.03

therefore

3,005 represent the initial value ( the amount of money for the value of x equal to zero)

6 0
3 years ago
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How many solutions does x²+3x=3 have?
aev [14]

Answer:

2 (real) solutions.

Step-by-step explanation:

A quadratic always has two solutions, whether they are real or complex.

Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).

In the case of

x^2+3x = 3, or

x² + 3x -3 = 0

we apply the quadratic formula to get

x =  (-3 +/- sqrt(3^2+4(1)(3))/2

to give the two solutions

{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}

both of which are real.

4 0
2 years ago
Which shows the expressions rewritten with the least common denominator?
baherus [9]

Answer:

  D.  (14x-4)/(8x^2) and (x^2-x)/(8x^2)

Step-by-step explanation:

The least common denominator will be 8x^2, the product of 2 and x to the highest of their powers in either of the denominators.

  \left\{\dfrac{7x-2}{4x^2},\ \dfrac{x-1}{8x}\right\}=\left\{\dfrac{7x-2}{4x^2}\cdot\dfrac{2}{2},\ \dfrac{x-1}{8x}\cdot\dfrac{x}{x}\right\}\\\\=\left\{\dfrac{14x-4}{8x^2},\ \dfrac{x^2-x}{8x^2}\right\}

7 0
2 years ago
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