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valina [46]
3 years ago
13

P = 4x + 3yx = 5y=-2(a) Work out the value of P.(b) Expand 4e(e + 2)​

Mathematics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

P=4×5+3×-2

P= 20x-6y

4e²+8e

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Lady bird [3.3K]
The answer is A) 176 
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3 years ago
X+(x+2)+(x+4)+(x+6)=4x+12=212
Mrac [35]

(x+(x+2)+(x+4)+(x+6))=4x+12=212

x+x+x+x(2+4+6)=4x+12=212

4x (2+4+6)=4x+12=212

4x(6+6)=4x+12=212

12+4x=4x+12=212

<u>-12            -12   -12</u>

4x=4x=200

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4 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
Oksana_A [137]
<h2>Hello!</h2>

The answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

7 0
3 years ago
Explain Steps. Do not answer. <br>#10 and 11<br>Questions are in the Picture
svet-max [94.6K]

Answer:

Step-by-step explanation:

For problem 10:

1. AE/ED=AC/CB (Since triangle ABC is similar to triangle ADE, we can determine that the ratio of AE to ED is equal to the ratio of AC to CB)

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For problem 11:

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2. AG/(AG+GB)=AE/(AE+ED) (Rewrite sides as the some of their parts)

3. 14/(14+7)=18/(18+x) (Substitute given values)

4. x=9 (Solve for x)

lmk if there are mistakes in my explanation, hope this helps :)

8 0
3 years ago
0612103993 please answer <br><br> 529185/(x/y-2)=3. solve for x and y
densk [106]

Answer: Y= x/176397

X= 176397y

Step-by-step explanation: I hope this helps. Have a brilliant day ! - Lily ^_^

4 0
3 years ago
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