2 years ago

If quadrilateral JKLM had a translation where all the vertices were in the second quadrant, what would be the vertices?

Mathematics

2 answers:

Volgvan2 years ago

6 0

D i think tho keep looking for clues

antoniya [11.8K]2 years ago

5 0

I believe it would be D because since its supposed to be in the second quadrant you go left first so the first number in the parenthesis (-4) and (-1) would be negative, making it possibly D.

You might be interested in

Decide if each answer will be less than or greater than the original number drag each to the correct category

Natalija [7]

Answer:

were is tha problem

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

PLEASE HELP ME ASAP

goblinko [34]

Answer:

20.04 units

Step-by-step explanation:

The diagram shows right triangle ABC. Use the definition of the cosine:

$\cos \angle C=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}\\ \\\cos \angle C=\dfrac{BC}{AC}\\ \\\cos 51^{\circ}=\dfrac{BC}{27}\\ \\BC=27\cdot \cos 51^{\circ}\\ \\BC\approx 20.04\ units$