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Andrew [12]
3 years ago
9

If quadrilateral JKLM had a translation where all the vertices were in the second quadrant, what would be the vertices?

Mathematics
2 answers:
Volgvan3 years ago
6 0
D i think tho keep looking for clues
antoniya [11.8K]3 years ago
5 0
I believe it would be D because since its supposed to be in the second quadrant you go left first so the first number in the parenthesis (-4) and (-1) would be negative, making it possibly D.
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A prop assistant needs to rent a telescope to use for a scene in a movie. One company charges $57 per day plus a flat fee of $32
vovangra [49]

The number of days for both Companies to have the same total amount is

6.4 days

<h3>Word Problem leading to Algebraic expression</h3>

 

Given Data

  • Let the total payment be y
  • Let the number of days be x

Company A

  • Charges per day = $57
  • Flat fee = $32

y = 57x+ 32 -----------------1

Company B

  • Charges per day = $62
  • Flat fee = $0

y = 62x + 0-----------------2

Equating 1 and 2 we have

57x+ 32 = 62x+ 0

Solving for x we have

62x-57x = 32

5x = 32

Divide both sides by 5

x = 32/5

x = 6.4 days

Learn more about word problem here:

brainly.com/question/13818690

5 0
2 years ago
125. Albert surveyed a class of 25 students on sports. 5 kids love baseball. 7 kids love basketball. 10 kids
MAXImum [283]

Answer:

3 students

Step-by-step explanation:

since the<em> </em>total number of students is 25,when you add those that like baseball, basketball and football the total number must be 25 but in this case it's 22 meaning 2 student liked neither.

7+5+10+x=25

x=25-22

=3

I hope this helps

4 0
3 years ago
Anyone know? I need help it’d be cool if someone gave the answer
photoshop1234 [79]

Answer: 19 units

Step-by-step explanation:

Count from A down then the left until you reach B.

8 0
3 years ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) P(X \leq 8) = 0.932 (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032 (cumulative)

(d) P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 (cumulative)

(e) P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251

5 0
3 years ago
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