If quadrilateral JKLM had a translation where all the vertices were in the second quadrant, what would be the vertices?

Mathematics

2 answers:

Volgvan2 years ago

6 0

D i think tho keep looking for clues

antoniya [11.8K]2 years ago

5 0

I believe it would be D because since its supposed to be in the second quadrant you go left first so the first number in the parenthesis (-4) and (-1) would be negative, making it possibly D.

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$\displaystyle\\
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30a - 30 = 5a^2-5\\\\
-5a^2 + 30a -30 + 5 =0\\\\
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5a^2 - 30a +25 = 0~~~~~\Big| : 5 \\\\
a^2 - 6a +5 = 0 \\ \\ 
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2 years ago

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QUESTION:

QUESTION:estimate the equation 12+19.61.

QUESTION:estimate the equation 12+19.61.Answer:

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Kryger [21]

Answer:

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Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

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