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uranmaximum [27]
3 years ago
11

How to we measure 1,energy? 2,Degrees 3,Anemometer 4,Barometer 5,Calories

Chemistry
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

calories

Explanation:

MERRY CHRISTMAS

Lelu [443]3 years ago
3 0

Answer:

anemometer i believe :)

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Complete the following equations (note that the equations are not balanced). Use the activity series if necessary. An activity s
umka21 [38]

The equation which we are required to complete can be completed as follows;

  • AgNO3 + KCl ==> KNO3 + AgCl

<h3>Electrochemical series;</h3>

Most substitution reactions involve displacement of metals and non-metals.

The possibility of a substitution reaction to occur is sometimes dependent on the order of preference of the metals in the activity series.

On this note, In the reaction between AgNO3 and KCl, potassium, K displaces silver, Ag and the products of the reaction are; KNO3 and AgCl

Read More on Electrochemical series;

brainly.com/question/14652325

8 0
2 years ago
Read 2 more answers
Use numbers to indicate the order of the steps in the titration process.
Snowcat [4.5K]

Answer:

7

5

1

8

3

6

2

4

just took on ed2020, good luck

7 0
3 years ago
Read 2 more answers
The reaction 2CH4(g)⇌C2H2(g)+3H2(g) has an equilibrium constant of K = 0.154. If 6.30 mol of CH4, 4.20 mol of C2H2, and 11.15 mo
boyakko [2]

Answer:

C₂H₂ + 3H₂ ⟶ 2CH₄  

Explanation:

The initial concentrations are:

[CH₄] = 6.30 ÷ 6.00 =   1.05  mol·L⁻¹

[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹

   [H₂] = 11.15 ÷  6.00 =  1.858 mol·L⁻¹

                2CH₄ ⇌ C₂H₂ + 3H₂

I/mol·L⁻¹:    1.05     0.700   1.858

Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07

Q > K

That means we have too many products.

The reaction will go to the left to get rid of the excess products.

C₂H₂ + 3H₂ ⟶ 2CH₄

8 0
4 years ago
Hello there!
Alenkasestr [34]

Answer:

Mass of carbon dioxide = 7.48 g

Explanation:

Given data:

Mass of lithium carbonate = 12.5 g

Mass of carbon dioxide produced = ?

Solution:

Chemical equation:

Li₂CO₃  →  Li₂O + CO₂

Number of moles of Li₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 12.5 g /73.89 g/mol

Number of moles = 0.17 mol

Now we will compare the moles of Li₂CO₃  with CO₂.

                   Li₂CO₃        :            CO₂

                     1                :               1

                  0.17             :             0.17

Mass of carbon dioxide:

Mass of carbon dioxide = number of moles × molar mass

Mass of carbon dioxide =   0.17 mol ×  44 g/mol

Mass of carbon dioxide = 7.48 g

4 0
3 years ago
What volume would be needed to prepare 375 mL of a .45 M CaCl2 using only a solution of 1.0 M CaCl2 and water?
Neporo4naja [7]

Answer:

168.75 ml

Explanation:

M1V1=M2V2

375ml*.45M=1M*V2

8 0
3 years ago
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