The equation which we are required to complete can be completed as follows;
- AgNO3 + KCl ==> KNO3 + AgCl
<h3>Electrochemical series;</h3>
Most substitution reactions involve displacement of metals and non-metals.
The possibility of a substitution reaction to occur is sometimes dependent on the order of preference of the metals in the activity series.
On this note, In the reaction between AgNO3 and KCl, potassium, K displaces silver, Ag and the products of the reaction are; KNO3 and AgCl
Read More on Electrochemical series;
brainly.com/question/14652325
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Answer:
C₂H₂ + 3H₂ ⟶ 2CH₄
Explanation:
The initial concentrations are:
[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹
[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹
[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹
2CH₄ ⇌ C₂H₂ + 3H₂
I/mol·L⁻¹: 1.05 0.700 1.858
![Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BC%24_%7B2%7D%24H%24_%7B2%7D%24%5D%5BH%24_%7B2%7D%24%5D%7D%5E%7B3%7D%7D%7B%5Ctext%7B%5BCH%24_%7B4%7D%24%5D%7D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B%200.700%5Ctimes%201.858%5E%7B3%7D%7D%7B1.05%5E%7B2%7D%7D%3D%204.07)
Q > K
That means we have too many products.
The reaction will go to the left to get rid of the excess products.
C₂H₂ + 3H₂ ⟶ 2CH₄
Answer:
Mass of carbon dioxide = 7.48 g
Explanation:
Given data:
Mass of lithium carbonate = 12.5 g
Mass of carbon dioxide produced = ?
Solution:
Chemical equation:
Li₂CO₃ → Li₂O + CO₂
Number of moles of Li₂CO₃:
Number of moles = mass/ molar mass
Number of moles = 12.5 g /73.89 g/mol
Number of moles = 0.17 mol
Now we will compare the moles of Li₂CO₃ with CO₂.
Li₂CO₃ : CO₂
1 : 1
0.17 : 0.17
Mass of carbon dioxide:
Mass of carbon dioxide = number of moles × molar mass
Mass of carbon dioxide = 0.17 mol × 44 g/mol
Mass of carbon dioxide = 7.48 g