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Yuri [45]
3 years ago
13

Synthesis gas (a mixture of CO and H2) is increased in concentration of hydrogen by passing it with steam over a catalyst. This

is the so-called water–gas shift reaction. Some of the CO is converted to CO2, which can be removed:
CO(g) + H2O(g) ⇄ CO2(g) + H2(g)
Suppose you start with a gaseous mixture containing 1.00 mol CO and 1.00 mol H2O.
When equilibrium is reached at 1000°C, the mixture contains 0.43 mol H2. What is the
molar composition of the equilibrium mixture?
Chemistry
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

n

Explanation: n

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Answer:

Step 1 should be convert atoms to moles (n). Step 2 should be convert moles (n) to mass (m).

Step 1

Use dimensional analysis to convert the number of atoms to moles.

1 mole atoms = 6.022 × 10²³ atoms

n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms) = 3.8193 mol Ag

Step 2

Convert the moles of Ag to mass.

mass (m) = moles (n) × molar mass (M)

n(Ag) = 3.8193 mol Ag

M(Ag) = atomic weight on the periodic table in g/mol = 107.868 g Ag/mol Ag

m(Ag) = 3.8193 mol × 107.868 g/mol = 412 g Ag = 410 g Ag rounded to two significant figures

The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.

Explanation:

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