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3 years ago

QUADRATIC FORMULA SIMPLIFIED PLZ HELP

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

Answer:

3x² + 5x + 1 = 0 simplified

x = (-5 ± $\sqrt{13}$ )/6 roots

Step-by-step explanation:

Given quadratic formula

3x² + 5x - 5 = - 6

Standard form

ax² + bx + c = 0

Simplifying

3x² + 5x - 5 + 6 = 0
3x² + 5x + 1 = 0

Solving

x = (-5 ± $\sqrt{5^2 -4*3*1}$ )/(2*3)
x = (-5 ± $\sqrt{13}$ )/6

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In the complex number system, which of the following is equal to

pogonyaev

Answer:

C) $122+154i$

Step-by-step explanation:

$(14-2i)(7+12i)\\\\(14)(7)+(14)(12i)+(-2i)(7)+(-2i)(12i)\\\\98+168i-14i-24i^2\\\\98+154i-24(-1)\\\\98+154i+24\\\\122+154i$

Therefore, C is correct. Recall that $i^2=-1$

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2 years ago

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Answer:

y=1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6=2(y+2)

6=(2)(y)+(2)(2)(Distribute)

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2 years ago

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pantera1 [17]

This sequence has generating function

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(if we include $k=0$ for a moment)

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$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

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Take the derivative one more time:

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so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

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Can someone help me?

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Answer:

Step-by-step explanation:

The answer is B because if you move two times to the right it gives you 0.09 like the eqution.

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Just reminder: B and D have the same result!! just different coefficient

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