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Lana71 [14]
2 years ago
15

What is the mean absolute deviation of the following set of data? 10,4,12,4,2,10,10,6

Mathematics
2 answers:
WITCHER [35]2 years ago
5 0

Answer:

4 and 2

Step-by-step explanation:

10,4,12,4,2,10,10,6

4 and 2

4+2=8

8/8=1

Katyanochek1 [597]2 years ago
3 0

Answer:

Step-by-step explanation:

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After rounding off, it would be 6%

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How many terms are in the algebraic expression 3x^2 + 4y - 1
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2 years ago
A psychology professor assigns letter grades on a test according to the following scheme. A: Top 10% scores, B: Scores below 10%
stich3 [128]

Answer:

The numerical limits for a D grade is between 57 and 64.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 71.5, \sigma = 9.5

D: Scores below the top 80% and above the bottom 7%

Between the 7th and the 100 - 80 = 20th percentile.

7th percentile:

X when Z has a pvalue of 0.07. So X when Z = -1.475.

Z = \frac{X - \mu}{\sigma}

-1.475 = \frac{X - 71.5}{9.5}

X - 71.5 = -1.475*9.5

X = 57.49

So 57

20th percentile:

X when Z has a pvalue of 0.2. So X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X - 71.5}{9.5}

X - 71.5 = -0.84*9.5

X = 63.52

So 64

The numerical limits for a D grade is between 57 and 64.

7 0
3 years ago
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