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Lana71 [14]
3 years ago
15

What is the mean absolute deviation of the following set of data? 10,4,12,4,2,10,10,6

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0

Answer:

4 and 2

Step-by-step explanation:

10,4,12,4,2,10,10,6

4 and 2

4+2=8

8/8=1

Katyanochek1 [597]3 years ago
3 0

Answer:

Step-by-step explanation:

You might be interested in
Kareem wrote the values shown below.
grandymaker [24]

Answer:

Option D is correct.

\lfloor 4.8 \rfloor  and \lceil 3.2 \rceil

Step-by-step explanation:

Floor function states that the greatest integer that is less than or equal to x.

It is represented by: \lfloor x \rfloor

Ceiling function states that the least integer that is greater than or equal to x.

It is represented by: \lceil x \rceil

As per the statement:-

Kareem wrote the values show below:

\lceil 3.2 \rceil,  \lfloor 2.7 \rfloor,  \lceil 2.9 \rceil and \lfloor 4.8 \rfloor.

by definition:

\lceil 3.2 \rceil = 4

\lfloor 2.7 \rfloor = 2

\lceil 2.9 \rceil=3

\lfloor 4.8 \rfloor = 4

From the given options only pair which is equivalent is:

\lfloor 4.8 \rfloor  and \lceil 3.2 \rceil

7 0
3 years ago
Solve the quadratic equation.<br> (x + 1)2 = 16<br> x = 3 or-5<br> x= -3 or 5<br> X = 35
Damm [24]

Answer:

X=7

(x - 3 )(x +5)

(x+3) (x-5)

X - 35

Step-by-step explanation:

(x + 1)2 = 16

Expanding , we have

2x + 2 = 16

2x = 16 - 2

2x = 14

X= 7.

4 0
3 years ago
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
What is the equation through the points: (-3, 10), (0, 4)<br><br><br> ASAP please
nexus9112 [7]

Answer:

y= -2x+4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A store pays $81 for a hockey stick and marks the price up by 5%. What is the amount of the mark-up?
OlgaM077 [116]
.05 is equal to 5%
So for every dollar the mark up is .05cents
So if you times $81 by .05 this will give you the mark up because each of the 81$ needs .05 added to it.

So $4.05 Is the mark up

And

The cost would be markup and original added together
4 0
3 years ago
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