1 year ago

What is the surface area of the sphere below?

Mathematics

1 answer:

madam [21]1 year ago

5 0

Answer:

Step-by-step explanation:

4^3 π = 64π units^2

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Work out the smallest integer value of x that satisfies the inequality 4x-3>22. ( I have not learned this question in maths )

matrenka [14]

4x>22+3

4x>25

x>25/4

x>6.35

5 0

2 years ago

Connor believed that he did not do well in his ABC physics test. All ABC physics test scores are normally distributed with a mea

jenyasd209 [6]

Answer:

Yes! he passed

Step-by-step explanation:

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2 years ago

Is the ratio 4.2:1.5 proportional to the rational 12.6:4.5

VARVARA [1.3K]

Answer:

YES

Step-by-step explanation:

cause 12.6 / 4.5 = 2.8

and 4.2 / 1.5 = 2.8

3 0

2 years ago

1. At a basketball championship game, students were polled and 82% of the students said that basketball is better than football.

zhuklara [117]

Step-by-step explanation:

(A)It says AT A BASKETBALL CHAMPIONSHIP so obviously most people there would’ve said basketball.

(B) Maybe try doing the whole school and not just the students at the basketball championship.

hope this helped! if you need anything else let me know. <3

8 0

2 years ago

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is $P(X=0) \approx 0.8659$

The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

3 0

2 years ago