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2 years ago

What is the first step in simplifying the expression?

1 answer:

7 0

(9 - 7 X 3 + 4 )²
Always follow the rule
BIDMAS

Brackets
Indices
Division
Multiplication
Addition
Subtraction

First look at the Brackets
There are no indices in the brackets
There is no division in the brackets
There is a Multiplication in the brackets    7 x 3

For the answer
(9 - 7 x 3 + 4)²
Brackets
Multiplication   7 x 3 = 21
(9 - 21 + 4)²
Addition   -21 + 4 = -17
(9 - 17)²
Subtraction    9 - 17 = -8
-8²

Now start again once the brackets are gone
-8²
Indices
-8 x -8 = 64

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Point-Slope Form Practice

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Answer:

$y=-x-7$

Step-by-step explanation:

Equation of straight line in point slope form is given as

$y-y_1=m(x-x_1)$

Here

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Therefore,

$y+5=-1(x+2)$

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2 years ago

If a system including the quadratic equation representing the parabola and a linear equation has no solution, which linear equat

marshall27 [118]

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Answer:

D. y=2x+6

Step-by-step explanation:

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2 years ago

Read 2 more answers

-7 < 3x + 2 < 5.<br> Solve for x

yarga [219]

Answer:

-3 < x < 1, This is the domain

5 0

2 years ago

The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p

Juliette [100K]

Check the picture below.

based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,

$\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)$

$\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}$

now, we can plug those values on A = (1/2)bh,

$\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5$

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2 years ago

$4 is what percent of $50? Round to the nearest tenth if necessary?

Assoli18 [71]

Answer

8 %( When we round off to the neaerest tenths we get 10%)

Step-by-step explanation

4/50*100

=4*2

=8%

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2 years ago