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3 years ago

14

I know the answer but I need the angle name pls hurry

2 answers:

Aloiza [94]3 years ago

6 0

Answer:

S

angle S would also be an obtuse angle measuring 118°

corresponding angle

Step-by-step explanation:

levacccp [35]3 years ago

6 0

Answer:

s.

Step-by-step explanation:

s is a corresponding angle to the 118 angle.

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4 years ago

Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)

andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR= $\sqrt{(-3-7)^2+(0-(-10))^2}$

QR= $\sqrt{(-10)^2+(10)^2}$

QR= $\sqrt{100+100}$

QR= $\sqrt{200}$ --------------------------(1)

QR=14.142136

RS= $\sqrt{(9-(-3))^2+(-8-0)^2}$

RS= $\sqrt{(12)^2+(-8)^2}$

RS= $\sqrt{144+64}$

RS= $\sqrt{208}$ ---------------------------(2)

RS=14.422205

QS= $\sqrt{(7-9)^2+(-10-(-8))^2}$

QS= $\sqrt{(-2)^2+(-2)^2}$

QS= $\sqrt{4+4}$

QS= $\sqrt{8}$ -------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

$RS^2 = QR^ +QS^2$

Substituting the values,

$(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2$

$208 = 200 +8$

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

8 0

3 years ago

Help!!! I’ll give brainliest

MrMuchimi

Answer:

B

Step-by-step explanation:

6 0

3 years ago

Give the radian measure of an angle drawn in standard position that corresponds with the ray containing the coordinate point (−1

Sergeu [11.5K]

Answer:

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point $(-12, -3\sqrt{2})$ is approximately $1.108\pi$ radians.

Step-by-step explanation:

With respect to origin, the coordinate point belongs to the third quadrant, which comprises the family of angles from $\pi\,rad$ to $\frac{3\pi}{2}\,rad$ . The angle in standard position can be estimated by using the following equivalence:

$\theta = \pi\,rad + \tan^{-1} \left(\frac{3\sqrt{2}}{12} \right)$

$\theta \approx \pi \,rad + 0.108\pi \,rad$

$\theta \approx 1.108\pi\,rad$

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point $(-12, -3\sqrt{2})$ is approximately $1.108\pi$ radians.

5 0

3 years ago