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Xelga [282]
3 years ago
15

Find values for p and q so that the equation has infinitely many solutions.

Mathematics
1 answer:
GaryK [48]3 years ago
3 0
Px-2= 4x+x+9

First what you should do is subtract the 2 on both sides

You’ll get px = 4x+x+7 then add the x to 4x

Px= 4x^2 +7

Dived the x on the left on both sides like this px/x = 4x^2+7/x

P= 4x+7
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Zeolite organized a canned food drive. She worked a total of 12 2/3 hours. She worked 3 1/6 hours each day that she worked. How
galina1969 [7]
She worked 4 days on the food drive because to do math with these two fractions, you have to give them the same denominator. So, 12 2/3 becomes 12 4/6. Then, how many times does 3 go into 12? 4 times so the answer is 4. Hope this helped :)
7 0
3 years ago
Write each equation in slope-intercept form.
Alexxx [7]

Answer:

A. y = -3/2x + 1

B. y = -5/3x + 10

C. y = -x + 6/5

Step-by-step explanation:

A. You just have to isolate the y so divide by 4: y = -3/2x + 1

B. 3y = -5x + 30

Divide by 3: y = -5/3x + 10

C. -5x + 6 = 5y

Divide by 5: -1x + 6/5 = y OR y = -x + 6/5

5 0
3 years ago
Read 2 more answers
Directions: Find the volume of each figure. Round to the nearest tenth if necessary.
balu736 [363]

Answer:

Step-by-step explanation:

square-based pyramid:

volume V = (⅓)b²h

    = (⅓)7²·16  

    ≅ 261.3 ft³

:::::

Can't help with question 3. I haven't learned triangle-based pyramids.

:::::

cone:

volume V = ⅓πr²h

              = ⅓π17²·20

              = 6052.8 yd³

:::::

can't help with question 7. Never did this kind of pyramid.

3 0
3 years ago
The function f(x) is an increasing function about which little else is known about other than f(2)=7 and f'(2)=5. Find (f^-1)'(7
andreyandreev [35.5K]

Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have

f^(-1)(f(x)) = x

Differentiating with the chain rule gives

(f^(-1))'(f(x)) f'(x) = 1

so that

(f^(-1))'(f(x)) = 1/f'(x)

Let x = a; then

(f^(-1))'(f(a)) = 1/f'(a)

(f^(-1))'(b) = 1/f'(a)

In particular, we take a = 2 and b = 7; then

(f^(-1))'(7) = 1/f'(2) = 1/5

3 0
3 years ago
Can someone help em with these questions?! Will mark brainiest!!!
Crazy boy [7]

The answers from questions 6 to 9 are A, C, D, and C.

8 0
4 years ago
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