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Xelga [282]
3 years ago
15

Find values for p and q so that the equation has infinitely many solutions.

Mathematics
1 answer:
GaryK [48]3 years ago
3 0
Px-2= 4x+x+9

First what you should do is subtract the 2 on both sides

You’ll get px = 4x+x+7 then add the x to 4x

Px= 4x^2 +7

Dived the x on the left on both sides like this px/x = 4x^2+7/x

P= 4x+7
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Answer: First, draw and label a number line. Then plot the five values that are given above the line. Draw a box from the lower quartile to the upper quartile, with a line dividing it at the median. Then draw lines from the minimum and maximum values connecting to the box to form the whiskers.

3 0
3 years ago
Sally goes to the store and buys a jackhammer for $25. The store is running a discount of 18%. The store has a sales tax rate of
tamaranim1 [39]

Answer:

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5 0
2 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
3 years ago
2p x 3q x 5r maths watch
Zepler [3.9K]

Answer:

2px^ 8 qr

Step-by-step explanation:

<u>Reformatting the input : </u>

Changes made to your input should not affect the solution:

(1): "x5"   was replaced by   "x^5".  1 more similar replacement(s).

<u>STEP  1 : </u>

<em><u>Equation at the end of step 1 </u></em>

 ((2px3 • q) • x5) • r

<u>STEP  2 : </u>

<u></u>

<em><u>Final result : </u></em>

 2px8qr

<u><em>HOPE THIS HELPS!</em></u>

<u><em> PLEASE MARK BRAINLIEST IF THIS HELPED YOU LEARN! :)</em></u>

3 0
3 years ago
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