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Norma-Jean [14]
3 years ago
11

Can someone please help

Mathematics
2 answers:
Juliette [100K]3 years ago
5 0

Answer:

201.06

Step-by-step explanation:

3.14 * 8^2= 201.06

(pi * radius ^ squared)

wlad13 [49]3 years ago
4 0
201.06 is the answer
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How many two-digit numbers are there in which the tens digit is greater than<br> the ones digit?
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there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

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7 0
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Step-by-step explanation:

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3 years ago
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professor190 [17]
Solution D 

Just put into a calculator 

Hope I helped :)

7 0
4 years ago
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