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2 years ago

9

Does anyone know the slope of this table?

1 answer:

ArbitrLikvidat [17]2 years ago

6 0

Answer: the slope is 2/1 or 2

Step-by-step explanation: slope is written rise over run, meaning y/x. By finding the difference between 13/5 and 17/7, then 17/7 and 21/9 to confirm, you can see that the difference is 4/2, which reduces to 2/1, which is simplified to 2.

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PLEASE HELP!!<br>solve for z<br>12 = 15 ( z - 1/5)<br><br>

cestrela7 [59]

Answer:

Z=1

Step-by-step explanation:

please mark me as brainlest

4 0

2 years ago

Read 2 more answers

Grayson needs to order some new supplies for the restaurant where he works. The restaurant needs at least 761 forks. There are c

Triss [41]

The restaurant needs at least 761 forks.

There are currently 205 forks

Each set on sale contains 10 forks,

The number of set taht have to buy are x

Number of forks in x set are = 10x

Since, we need at least 761

So 761 should be graeter than equal to the sum of reamining forks and the new forks

i.e. 761 ≥ 10x + 205

Answer : 3. 761 ≥ 10x + 205

7 0

8 months ago

Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.

torisob [31]

Fermat's little theorem states that
$a^p$ ≡a mod p

If we divide both sides by a, then
$a^{p-1}$ ≡1 mod p
=>
$a^{17-1}$ ≡1 mod 17
$a^{16}$ ≡1 mod 17

Rewrite
$a^{1000000}$ mod 17 as
$=(a^{16})^{62500}$ mod 17
and apply Fermat's little theorem
$=(1)^{62500}$ mod 17
=>
$=(1)$ mod 17

So we conclude that
$a^{1000000}$ ≡1 mod 17

6 0

3 years ago

S^2+3s-10=0 complete the square and show your work so I can learn how to do it please and thanks!

Volgvan

S^2+3s-1”=0 pls give Brainliest Im BEGGING

5 0

2 years ago

Read 2 more answers

A sequence of 7 numbers starts with 8. The second number in the sequence is unknown and may be positive or negative. The third t

scoray [572]

Answer:

4

Explanation:

$a_1=8,a_7=0$

Since the third term is the sum of the two previous terms

$a_3=a_2+a_1$

$a_7=a_6+a_5$

$a_7=a_5+a_4+a_4+a_3$

Continuing in like manner

$a_7=5a_3+3a_2$

Since $a_3=a_2+a_1$

$a_7=5(a_2+a_1+3a_2$

$a_7=5a_2+5a_1+3a_2$

$a_7=8a_2+5a_1$

Recall: $a_1=8,a_7=0$

$0=8a_2+5*8$

$8a_2=-40$

$a_2=-5$

The sequence is therefore:

8,-5,3,-2,1,-1,0

The sum of the seven numbers is 4.

8 0

3 years ago