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Dafna1 [17]
3 years ago
9

Does anyone know the slope of this table?

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer: the slope is 2/1 or 2

Step-by-step explanation: slope is written rise over run, meaning y/x. By finding the difference between 13/5 and 17/7, then 17/7 and 21/9 to confirm, you can see that the difference is 4/2, which reduces to 2/1, which is simplified to 2.

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Answer:

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Step-by-step explanation:

The equation would be y = -2x+3. If we take y+2x=3, and subtract 2x from both sides, we get y = -2x+3, which is the right equation.

5 0
3 years ago
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Use complete sentences to explain why absx + 2 > \absx.
12345 [234]

The value of |x| + 2 is always positive and greater than |x|.

The correct question is as below:-

Use complete sentences to explain why |x| + 2 > |x|.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The given expression is as follows:-

|x| + 2 > |x|.

Here x is in the mode so any number either negative or positive it will always give you a positive number. For an example put x = -5 in the above expression.

|-5| + 2 > | -5 |

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Put -1 at the place of x

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As we can see in the above two examples for every value of x there will be a positive number and the value of |x|+2 is always greater than |x|.

Therefore the value of |x| + 2 is always positive and greater than |x|.

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5 0
2 years ago
A university cafeteria line in the student center is a
nirvana33 [79]

Answer:

Lamda= 4 students/min, µ= 5 students/min  

P= Lamda/µ= 4/5= 0.8

a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2

b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5-  - .2 - (.8)*.2 – (.2)*.8^2))= 0.848

Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768

c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes

d.) L(q)= lamda*W(q)= 4*.8= 3.2 students

e.) L(System)= lamda/(µ-lamda)= 4 students.

f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.

P= 4/10= 0.4

Probability that system is empty= P0= 1-.4= 0.6

W(q)= 4/10(10-4)= 0.0667 minutes

L(q)= Lamda*W(q)= 4*.0667=0.2668

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

b

Step-by-step explanation:

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