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aalyn [17]
3 years ago
12

What produces toxic chemicals in the body?

Biology
1 answer:
PSYCHO15rus [73]3 years ago
7 0

Explanation:

<h2>Chemicals can be toxic because they can harm us when they enter or contact the body. Exposure to a toxic substance such as gasoline can affect your health. Since drinking gasoline can cause burns, vomiting, diarrhea and, in very large amounts, drowsiness or death, it is toxic.</h2>
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The long "tail" on a detergent molecule is made up mostly of carbon atoms bonded to other carbon atoms. Why would you expect the
Ivahew [28]

Answer:

A detergent molecule consists of a polar ionic head and a non polar hydrocarbon tail. Polarity of a molecule is due to difference in electronegativities of constituting atoms. For example O-H bond is polar because oxygen is very electronegative compared to hydrogen (3.44 vs 2.2) so O acquires a partial negative charge and H acquires a partial positive change making the bond polar.

Detergent tail molecule is non polar because it is made of hydrocarbons i.e. hydrogen and carbon atoms. Carbon atoms are bonded to each other and to hydrogen atoms. Electronegativities of carbon and hydrogen are almost same ( 2.55 and 2.2 respectively ). The difference is not much to induce polarity in C-H bond also hydrocarbon tails have maximum C-C bonds which have no polarity because both the atoms are same.Hence, the tail of detergent molecule is non polar.

3 0
3 years ago
Most organisms can be divided into two categories - prokaryotes and eukaryotes. What is the main difference between these two ca
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Eukaryotic'so have a nucleus
7 0
3 years ago
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A large stored sugar found in plant roots, fruits and seeds
bonufazy [111]
  • Plants convert glucose into starches and they store it into seeds and roots and the simple sugar glucose is converted into fructose to be stored into fruits.
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5 0
3 years ago
As discussed previously, the ABO locus in humans has three alleles, where IAand IBare co-dominant and i is recessive to each. Su
Ivahew [28]

Answer:

Explanation:

using the formula p² + 2pq + 2pr + q²+ 2qr + r² = 1 where p is IA allele is 0.35 and q is IB allele is 0.15.

Thus, the expected frequency of people with type AB blood in this population will be (2pq) = 2 x 0.35 x 0.15 = 0.105

b. The expected frequency of people with type A blood will be p² + 2pr = where r is found using the formular p + q + r = 1 = 1 - (p+q) = 1 - (0.35+0.15) = 0.5

Thus, we have the expected frequency of people with type A blood to be     (0.35² + 2x0.35x0.5) = 0.4725.

c.    <u> p² + 2pr</u> + <u>2pq </u>+ <u>q² + 2qr</u> +<u> r²</u>

       AA AO      AB      BB BO     OO

         1850       180        635      2335

frequency of IA- p = (1850 + 180/2) / 5000 = 0.388

frequency of IB- q = (635 + 180/2) / 5000 = 0.145

frequency of i- r = 2335/ 5000 = 0.467.

since r² = 2335, r = √2335 = 48.32

using the formula p + q + r = 1

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