Answer:
y=5/2x+3 or
Step-by-step explanation:
<u>Step 1:</u>
Compute the slope (-4, -7), (2,8):
m=5/2
<u>Step 2:</u>
Compute the y intercept:
b=3
<u>Step 3:</u>
Add the results together:
y=5/2x+3 or
Hence, the final answer is y=5/2x+3 or
<em>Greetings from Brasil...</em>
One way to solve this question is through determinant
| X Y 1 |
| X₁ Y₁ 1 | = 0
| X₂ Y₂ 1 |
We have:
(X₁; Y₁) = (-4; -7)
(X₂; Y₂) = (2; 8)
then
| X Y 1 |
| -4 -7 1 | = 0
| 2 8 1 |
<h3>- 15X + 6Y - 18 = 0</h3>________________________________
<em>see something similar in</em>
<em>brainly.com/question/28654988</em>
Given:
The limit problem is:
To find:
The value of the given limit problem.
Solution:
We have,
In the function , the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.
So, the function approaches to positive infinity as x approaches to negative infinity.
Therefore, .
9514 1404 393
Answer:
1. asymptotes: x=-6, x=6, y=0; zero: x=0
2. 20 blue fish
Step-by-step explanation:
1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.
The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.
The zero is where the numerator is zero, at x=0.
In summary:
__
2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.
blue fish = 2×10 = 20 fish
<em><u>Check</u></em>
There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.
<u><em>Additional comment</em></u>
I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...
r = 60%(r + b) . . . . reds are 60% of the total
r - b = 10 . . . . . . . . 10 more reds than blues
We want the value of b, so we can eliminate r by substituting for it:
r = 10 + b . . . . from the second equation above
(10 +b) = 0.60((10 +b) + b) . . . . substitute for r
10 +b = 6 + 1.2b . . . simplify
4 = 0.2b . . . . subtract b+6
20 = b . . . . . . multiply by 5 (there are 20 blue fish)
