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1 year ago

What is an equation of the line that passes through the points (-4,-7) and (2,8)

Mathematics

2 answers:

Alenkasestr [34]1 year ago

7 0

Answer:

y=5/2x+3 or $y=\frac{5}{2}x+3$

Step-by-step explanation:

Step 1:

Compute the slope (-4, -7), (2,8):

m=5/2

Step 2:

Compute the y intercept:

b=3

Step 3:

Add the results together:

y=5/2x+3 or $y=\frac{5}{2}x+3$

Hence, the final answer is y=5/2x+3 or $y=\frac{5}{2}x+3$

ad-work [718]1 year ago

7 0

Greetings from Brasil...

One way to solve this question is through determinant

| X Y 1 |

| X₁ Y₁ 1 | = 0

| X₂ Y₂ 1 |

We have:

(X₁; Y₁) = (-4; -7)

(X₂; Y₂) = (2; 8)

then

| X Y 1 |

| -4 -7 1 | = 0

| 2 8 1 |

________________________________

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max2010maxim [7]

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3 years ago

Can you please answer this

jasenka [17]

Answer:

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36 + 39 + BHD = 180

BHD = 180 - 36 - 39

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3 years ago

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valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

$M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

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So, the coordinates of B is (-8,-5).

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