Question

What is an equation of the line that passes through the points (-4,-7) and (2,8)

Answer 1

Answer:

y=5/2x+3 or $y=\frac{5}{2}x+3$

Step-by-step explanation:

Step 1:

Compute the slope (-4, -7), (2,8):

m=5/2

Step 2:

Compute the y intercept:

b=3

Step 3:

Add the results together:

y=5/2x+3 or $y=\frac{5}{2}x+3$

Hence, the final answer is y=5/2x+3 or $y=\frac{5}{2}x+3$

Answer 2

Greetings from Brasil...

One way to solve this question is through determinant

| X     Y     1 |

| X₁    Y₁    1 |  = 0

| X₂    Y₂   1 |

We have:

(X₁; Y₁) = (-4; -7)

(X₂; Y₂) = (2; 8)

then

| X   Y   1 |

| -4  -7   1 |  = 0

| 2   8    1 |

- 15X + 6Y - 18 = 0

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