If cash prizes are to be avoided, then . . .
-- The first prize has to be a car.
-- The second prize can be a motorbike or a trip ... 2 possibilities.
For each of those . . .
-- The third prize has to be a TV.
Since there's no choice with the first or third prizes,
I only see two different ways to avoid a cash prize.
Can I see the question ?
There isn’t a question ..???
Subtract 28 from 412 and then divide that answer by 12
Hey there!
Question #1
-3(3 + 7)
3 + 7 = 10
-3(10)
= -30
Question #2
-3[(-6)×3]
-6(3) = -18
-3(-18)
= 54
Question #1
Answer: -30
Question #2
Answer: 54
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer:
A Similar.
Step-by-step explanation:
Similar.
To be congruent they must have equal sides as well as the same shape.