1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
Answer:
import random
randomlist = []
for i in range(0,20):
n = random.randint(-29,30)
if n < 0 :
n = 100
randomlist.append(n)
print(randomlist)
Explanation:
The random module is first imported as it takes care of random. Number generation.
An empty list called randomliay is created to hold the generated random integers.
Using a for loop, we specify the range of random numbers we want.
Inside the for loop ; we attach our generated random integer which will be in the range (-29 to 30) in a variable n
For each n value generated, if the value is less than 0( it is negative, since all the values are integers), replace the value with 100.
The answwer to the type of hardware is led lighting it does not need a inverter
B) a desktop is less likely to be stolen or damaged
