X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
B
Step-by-step explanation:
A is on the x axis
B is on the y axis
C is on the x axis
you don't list any expressions to choose from but
if width = x
and length = 2x
Area = 2x * x
Area = 2x^2
Answer:
No parallel lines will never intersect.
Step-by-step explanation:
They go in the same direction almost like an equals sign "="
Answer:
Number of children, x= 400
Number of adults, y = 100
Step-by-step explanation:
Let the number of children be x
Let the number of adults be y
Given : Total number of people, x + y = 500 --------(1)
Total amount collected, 5x + 10y = 3000 ---------(2)
(1) => y = 500 - x
Substitute y in (2) : 5x + 10(500 - x) = 3000
5x + 5000 - 10x = 3000
-5x = 3000 - 5000
-5x = -2000
x = 400
Substitute x in (1) : 400 + y = 500
y = 500 - 400
y = 100
