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Igoryamba
3 years ago
7

¿Cuántos gramos de dióxido de carbono (CO2) se producen si se quema 40 gramos del hidrocarburo ( C3H8 )?

Biology
1 answer:
Valentin [98]3 years ago
3 0

Answer:

120 gramos de CO₂

Explanation:

La ecuación química balanceada para la reacción de combustión del hidrocarburo C₃H₈ (propano) es la siguiente:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Por lo tanto, 1 mol de C₃H₈ produce 3 moles de CO₂. Ahora debemos convertir las moles a gramos utilizando el peso molecular (PM) de cada compuesto:

PM(C₃H₈)= (3 x 12 g/mol) + (8 x 1 g/mol) = 44 g/mol

1 mol C₃H₈ = 1 mol x 44 g/mol = 44 g

PM(CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

3 mol CO₂ = 3 mol x 44 g/mol = 132 g

Por lo tanto, se producen 132 gramos de CO₂ a partir de 44 gramos de C₃H₈ y la relación estequiométrica es:

3 mol CO₂/1 mol C₃H₈ = 132 g CO₂/44 g C₃H₈

Finalmente, para calcular cuántos gramos de CO₂ se producen al quemar 40 g de C₃H₈, multiplicamos la relación estequiométrica por la masa a quemar:

masa CO₂ producida = 40 g C₃H₈ x 132 g CO₂/44 g C₃H₈= 120 g

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