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VARVARA [1.3K]
3 years ago
8

6 numbers are shown

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

-1\frac{1}{2}, -\frac{3}{4}, -\frac{37}{50}, \frac{5}{4}, 1\frac{1}{4}, 2\frac{3}{4}

Step-by-step explanation:

1\frac{1}{4} , -1\frac{1}{2},  -\frac{37}{50}, -\frac{3}{4}, 2\frac{3}{4},  \frac{5}{4}

Order everything, negative to the left side and positive to the right side

<u><em>Negative numbers:</em></u>

-1\frac{1}{2}, -\frac{37}{50}, -\frac{3}{4}

<u><em>Positive numbers:</em></u>

1\frac{1}{4}, 2\frac{3}{4}, \frac{5}{4}

<em><u>Now order it on a number line:</u></em>

-1\frac{1}{2}, -\frac{3}{4}, -\frac{37}{50}, \frac{5}{4}, 1\frac{1}{4}, 2\frac{3}{4}

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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
In a math class there are 8 male students and 7 female students. A
DanielleElmas [232]

Answer:

Step-by-step explanation:

6 0
3 years ago
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The wind speed s (in miles per hour) is related to the distance (in miles) the tornado travels by the equation s = 93log d + 65.
Vesnalui [34]

Answer:

The distance the tornado traveled was approximately 205 miles.

Step-by-step explanation:

The equation representing the relationship between the wind speed (in miles per hour) and the distance the tornado travels (in miles) is:

s=93\log d+65

Compute the value of <em>d</em> for <em>s</em> = 280 as follows:

        s=93\log d+65

     280=93\log d+65

93\log d=280-65\\93\log d=215

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Thus, the distance the tornado traveled was approximately 205 miles.

7 0
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4 0
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128 POINTS IF YOU HELP
Aleksandr-060686 [28]
(A) We let y = the cost and are told x = the number of people. Since you pay $20 per person, the cost is 20x. That is, y=20x

(B) Again, let the cost =y and the number of people is given as x. You pay $10 per person or 10x plus an additional $50 for the room. That is, y=10x+50

(c) Link to graphs: https://www.desmos.com/calculator but if that doesn't work see the attachment for a screen shot. You just have to put the equations (type them) at left and the graph comes automatically.

(D) The admission price is the same when the two equations are equal. You can find this by setting them equal to each other as such: 20x = 10x+50 and solving for x. However, since you just graphed them the point of intersection (where the lines share/have the same point) gives the information. Remembers that (x,y) = (people, cost). The graphs intersect at (5, 100) so for 5 people the cost is the same and the cost is $100.

(E) For the regular rate we let x = 6 and solve for y (the cost). We get y = 20x which is y = (20)(6)=120. It costs $120 using the regular rate to take 6 people. Now let's use the equation for the group rate again with x = 6. Here we get y = 10x +50 or y = 10(6)+50 = $110. The group rate costs $110.

(F) The cost is the same at 5 people but if there are more than five the group rate is better as we saw in part E. So the regular rate is better for less than 5 people.

(G) Here y = $150. Let us use the group rate formula and solve for x (the number of people). 10x+50 = 150 so 10x = 100 and x = 10. Since 10 is more than 5 this is the better deal. However if you don't believe it or want to double check we can solve for x using y = 150 and the regular rate equation. We get: 20x = 150 so x = 7.5 Since we can't bring half a person we would only be able to bring 7 and that is less than 10 so this is not the best choice. Use the group rate and bring 10 people!

8 0
3 years ago
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