The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
<h3>What is the distance?</h3>
Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An object is traveling at a steady speed of 10 1/5 mi/h.
u = 10 1/5 min/h
u = 51/5 min/h
As we know, the speed-distance relationship:
time = distance/speed
distance = 1 4/5 = 9/5
time = (9/5)/(51/5)
time = 9/51 hours
time = (9/51)60
time = 10.58 minutes
Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
Learn more about the distance here:
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Answer:
A. tan 38° = opposite/adjacent
opposite = (tan 38°)(adjacent)
opposite = (0.31)(17 ft)
opposite = 5.27 ft
B. height is = 5.27 ft
Interest=percent times rate(in years) times principal.
Or I=PRT
So you invest $580 so I=$580 Rate would be .10 and time would be 1 for one year. So if you put this into the formula you get
$580=P(.65)(1)
So $580=.65P so $580/.65=P so P is approximately $892.31 per year.
11 would be my best guess, kinda confusing question. I hope I helped!
I think the answer would be d
