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<h3>
Answer: c. 8(y-6) = (x-2)^2</h3>
Explanation:
The directrix is horizontal, so the axis of symmetry is vertical. We'll have an x^2 term. The vertical distance from y = 4 to y = 8 is 4 units. Cut this in half to get 2, which is the focal distance p = 2.
The point (2,4) is directly below (2,8), and the point is on the directrix. The midpoint between (2,4) and (2,8) is (2,6). This is the vertex.
(h,k) = (2,6)
4p(y-k) = (x-h)^2
4*2(y-6) = (x-2)^2
8(y-6) = (x-2)^2
Step-by-step explanation:
F(x) = ∫ₐˣ t⁷ dt
F(x) is the area under f(t) between t=a and t=x. When x=a, the width of the interval is 0, so the area is zero.
F(6) = 0, so a = 6.
F(x) = ∫₆ˣ t⁷ dt
F(6) = ∫₆⁶ t⁷ dt
F(6) = 0
Answer:
x -2y -2=0
Step-by-step explanation:
using the formula, m= ( Y2 - Y1)/( X2-X1)
the gradient is found. the coordinates chosen are (2,0) and ( 0,-1)
the equation of the line is obtained using the formula
y -y1= m(x -x1)
Answer:
-19.68
Step-by-step explanation:
(0.2 + (-5) × (4.1)
-4.8 × (4.1)
-19.68