Hello
let : f(x) = 6 + √(14+x) - <span>√(9x)
f(2) = </span>6 + √(14+2) - √(9×2)
f(2) = 6 + √(16)-√(18)
f(2) = 6 + 4 - √(18) = 10 - √(18)
Answer:
I believe d
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>


Answer:
Because you have to get the answer
Step-by-step explanation: