Answer:
Total amount of alum lost = 0.5122 grams
Explanation:
Let the total volume of the solution be 100 mL
In 100 mL of solution, there is 2.63 gram of alum.
Out of this 100 mL solution, 42.5 mL is remaining.
Amount of alum in 42.5 mL solution is
grams
Now the amount of alum lost is 
grams
Answer:
Percent yield = 94.5%
Theoretical yield = 26.89 g
Explanation:
Given data:
Mass of copper = 12.5 g
Mass of copper chloride produced = 25.4 g
Theoretical yield = ?
Percent yield = ?
Solution:
Cu + Cl₂ → CuCl₂
Number of moles of Copper:
Number of moles = mass/ molar mass
Number of moles = 12.5 g/ 63.55 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of copper with copper chloride.
Cu : CuCl₂
1 : 1
0.2 : 0.2
Theoretical yield:
Mass of copper chloride:
Mass = Number of moles × molar mass
Mass = 0.2 mol × 134.45 g/mol
Mass = 26.89 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 25.4 g/26.89 g × 100
Percent yield = 94.5%
Fe(OH)3 --> Fe2O3 + H2O
2 Fe(OH)3 --> Fe2O3 + 3H2O
I hope this helps!
