The molecular formula for tin(IV) sulfate is Sn(SO₄)₂.
mass of sulfur S = 32.065
as there is 2 sulfur in tin (IV) sulfate = 32.065 x 2 = 64.13
mass of oxygen = 15.999 and there are 8 oxygen atoms in the formula;
8 x 15.999 = 127.992
mass of tin = 118.71
now add all the masses = 64.13 + 127.992 + 118.71 = 310.832
formula mass of tin(IV) sulfate is 310.832
2.5 x 10^24 molecules of C4H10
Density = mass/volume = 316/22.5 = 14.045g/mL.
Answer:
B = CHCl2 + Cl2 --> CHCl3 + Cl
Explanation:
Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.
Free radical chlorination is divided into 3 steps which are:
The initiation step
The propagation step
The termination step
So in reference to the question, propagation step involves two steps.
The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.
The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.
You would find in the attachment the 2 step mechanism.