See the attached figure
radius of the circle = r = 6
the length of one side of the equilateral triangle = L
the height if the triangle = h
The shaded area is the required area.
∴The area = (1/3) (area of circle - area of triangle )
area of circle = π r² = π * 6² = 36 π
An equilateral triangle is inscribed in a circle of radius r
∴ The length of one side of the triangle = √3 * r
= 6√3
and the height of the triangle = (√3 /2) * 6√3 = 9
∴ Area of the triangle = 0.5 * 9 * 6√3 = 27√3
The required area = (1/3) (area of circle - area of triangle )
= (1/3) * ( 36π - 27√3 )
= 12π - 9√3
Answer:
the first one and the last one
Step-by-step explanation:
the other 2 have numbers above 1.
Answer:
a) P(A')=0.7.
b) P(B')=0.75.
c) P(C')=0.4.
d) d) Therefore, we conclude that are A and B mutually exclusive events.
Step-by-step explanation:
From task we know that are:
P(A)=0.3
P(B)=0.25
P(C)=0.6
Therefore, we get calculate the next probabilities:
a) P(A')=1-P(A)
P(A')=1-0.3
P(A')=0.7.
b) P(B')=1-P(B)
P(B')=1-0.25
P(B')=0.75.
c) P(C')=1-P(C)
P(C')=1-0.6
P(C')=0.4.
d) Therefore, we conclude that are A and B mutually exclusive events.
Answer:
n=0
Step-by-step explanation:
(n-3) * (-6) = 18
Divide each side by -6
(n-3) * (-6)/ -6 = 18/-6
n-3 = -3
Add 3 to each side
n-3+3 = -3+3
n = 0
The average rate of change of a continuous function, <span>f<span>(x)</span></span> , on the closed interval <span>[a,b]</span> is given by
<span><span><span>f<span>(b)</span></span>−<span>f<span>(a)</span></span></span><span>b−a</span></span>