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umka21 [38]
3 years ago
12

I am dying from these math questions

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
It's base area times height.
so if you arrange the net patterns in such a way that 6 yard is it's height then it's base are would be 8yd²
therefore, volume of solid = 48 yd³
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A compound proposition that is always ___________ is called a contradiction. A. True B. False
alexandr1967 [171]

Answer:

<em>A compound proposition that is always false is called a contradiction</em>

Step-by-step explanation:

3 0
2 years ago
If p(x)= 2^x, what is the value of p(3) - p(2)?
rjkz [21]

Answer:

4

Step-by-step explanation:

p(3) = 2³ = 8

p(2) = 2² = 4

8-4 = 4

4 0
2 years ago
Which of the following are situations that can be modeled with a quadratic function? Select all that apply.
Lina20 [59]

Answer:

Option 2 and 5 are correct.

Step-by-step explanation:

We need to tell which one of them is quadratic function.

Option 1 is exponential decay so, it is not quadratic.

Option 2 is quadratic because the diver will take the parabolic shape when jumps.

Option 3 is not quadratic.Option 4 is not quadratic it is linear.

Option 4 is again exponential not quadratic.

Option 5 is quadratic because it takes the parabolic shape again.


4 0
3 years ago
Read 2 more answers
2×3 squared<br><img src="https://tex.z-dn.net/?f=2%20%5Ctimes%203%20%7B%3F%7D%5E%7B2%7D%20" id="TexFormula1" title="2 \times 3 {
morpeh [17]
2 x 3^2
2 x 9
18

18 is the answer
3 0
2 years ago
Read 2 more answers
The endpoints of GH are G(3,3) and H(-7,7).<br> Find the coordinates of the midpoint M.
sesenic [268]

Step-by-step explanation:

Hey there!!

You can simply use midpoint formulae to find midpoint of the coordinates.

Here, Given that;

G(3,3) and H(-7,7).

Using midpoint formulae,

midpoint \: of \: gh =  (\frac{x1 + x2}{2}  ,\frac{y1 + y2}{2})

midpoint \: of \: gh =  (\frac{3 - 7}{2}  ,\frac{3 + 7}{2})

After simplifying it we get,

= (-2,5).

Therefore, midpoint of GH is M(-2,5).

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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