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vazorg [7]
3 years ago
6

Is (-2, 6) a solution to this system of linear equations? (HINT: Substitute x

Mathematics
1 answer:
Serggg [28]3 years ago
5 0

Answer:

1st Equation: -8x + y = 22

At (-2,6)

(-8*-2)+ 6 =16+6= 22: That is correct

2nd Equation: -8x - y =10

At (-2,6)

(-8*-2)-6= 16-6= 10: That is correct

Both are correct.

Hope it helps you.

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Math help plz! Check for extraneous solutions. Giving brainlist
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3 years ago
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

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3 years ago
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Answer:

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Step-by-step explanation:

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Find the least common multiple of 10 and 14.
aksik [14]
We can do this by just adding 14 to 14 until we get a number that is divisible by 10.  We can do it this way because it will be a small number.  Let's list them out.  14, 28, 42, 56, 70.  70 is divisible by 10, so 70 is the answer.
8 0
3 years ago
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