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irina [24]
3 years ago
8

Find the equation of a line perpendicular to 4x-y=4 that contains the points (0,3)​

Mathematics
1 answer:
wolverine [178]3 years ago
4 0

9514 1404 393

Answer:

  x + 4y = 12

Step-by-step explanation:

The perpendicular line can be found by swapping the x- and y-coefficients and negating one of them. Then those new coefficients can be used with the coordinates of the given point to find the required constant.

  line: 4x -y = 4

  perpendicular line: x +4y = constant

Through (0, 3):

  0 +4(3) = constant = 12

The perpendicular line has standard form equation x +4y = 12.

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Good afternoon, 

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\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

\qquad \sf  \dashrightarrow \:  \dfrac{15}{1.45} \:  \:  ft / sec

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\qquad \sf  \dashrightarrow \:  \dfrac{15}{1.45} \:  \:   \times 3.5 \times 60

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