3 years ago

Which inequalities are true plz help!!!

Mathematics

2 answers:

VashaNatasha [74]3 years ago

4 0

2,3, and 5 are the answers.

alex41 [277]3 years ago

3 0

Answer:2,3, and 5

Step-by-step explanation:

You might be interested in

HELP!!!!!!!!!!!!!

Misha Larkins [42]

Answer:

P'(7,0)Q'(2,1) R'(12,-6)

Step-by-step explanation:

P(3,5)------>P'(3+4,5-5)

P'(7,0)

Q(-2,6)----->Q'(-2+4,6-5)

Q'(2,1)

R(8,-1)------>R'(8+4,-1-5)

R'(12,-6)

8 0

4 years ago

Anyone please help me

QveST [7]

Standard form of a quadratic equation: ax^2 + bx + c = 0

4x^2 - 5x + 10 = 2x

4x^2 - 7x + 10 = 0

Hope this helps!

6 0

3 years ago

Sum and difference tan(135+30)

Mumz [18]

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\sin y\cos x}{\cos x\cos y-\sin x\sin y}=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

So,

$\tan(135^\circ+30^\circ)=\dfrac{\tan135^\circ+\tan30^\circ}{1-\tan135^\circ\tan30^\circ}$

You should know that $\tan135^\circ=-1$ and $\tan30^\circ=\dfrac1{\sqrt3}$

Putting everything together,

$\tan(135^\circ+30^\circ)=\dfrac{-1+\dfrac1{\sqrt3}}{1-(-1)\left(\dfrac1{\sqrt3}\right)}=\dfrac{1-\sqrt3}{\sqrt3+1}=\sqrt3-2$