The triangles consist in rectangles ΔABD and ΔCDB are congruent triangles.
Given that,
To prove ΔABD ≅ ΔCDB.
<h3>What is congruent geometry?</h3>
In congruent geometry, the shapes that are so identical. can be superimposed on themselves.
Here,
consider ΔABD and ΔCDB
1. AB = CD [opposite sides of a rectangle]
2. ∠A = ∠C [each angle of the rectangle is 90°]
3. AD = BC [opposite sides of a rectangle]
ΔABD ≅ ΔCDB
Thus, Both triangles ΔABD ≅ ΔCDB are congruent triangles, hence proved.
Learn more about congruent geometry here. brainly.com/question/12413243
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