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2 years ago

Help me with this asap right now please i will mark brainlest

Mathematics

1 answer:

Rainbow [258]2 years ago

4 0

Answer:

5(8x+6y) & 10(4x+3y) & 2(20x+15y)

Step-by-step explanation:

the first doesn't include y, the third is too large, the fifth has y in the multiplier.

the only left are the fourth and second and sixth.

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What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?

posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

$\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\$

$Since\ \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0$

5 0

2 years ago

A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+

Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

$C(x) = 4 + 0.10(x-70)$

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

$C(x) \geq 7$

$4 + 0.10(x - 70) \geq 7$

$4 + 0.10x - 7 \geq 7$

$0.10x \geq 10$

$x \geq \frac{10}{0.1}$

$x \geq 100$

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

$C(x) \leq 8$

$4 + 0.10(x - 70) \leq 8$

$4 + 0.10x - 7 \leq 8$

$0.10x \leq 11$

$x \leq \frac{11}{0.1}$

$x \leq 110$

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0

3 years ago

Solve for x. Explain the steps taken to find the solution.<br><br> 3/2 + 3x/5 = 9/2 4x/5

Iteru [2.4K]

Answer:

i just got it right

7 0

2 years ago

What is the area, in square meters, of the isosceles trapezoid below?

Greeley [361]

Answer:

Where is the triangle?

you might have to add a picture or a worded problem

Step-by-step explanation:

3 0

2 years ago

Describe the graph of the function.y = |x – 4| – 7

juin [17]

This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x
Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Hope it helps, despite being this long!

3 0

2 years ago

Read 2 more answers