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kifflom [539]
3 years ago
10

I need help on questions 2,3,4,5 just to make sure pls ASAP

Mathematics
1 answer:
Stolb23 [73]3 years ago
6 0
True false true true
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Using the formula find the slope of a line with the points (10,20) and (30,50).
VARVARA [1.3K]

Answer:

m = 2/3

Step-by-step explanation:

Slope is defined as the ratio rise/run.

As we move from (10, 20) to (30, 50), the run is 30 - 10, or 20, and the rise is 50 - 20, or 30.  Thus, the slope of the line is m = 30/20, or 2/3.

3 0
3 years ago
Please I need help with this!!!!!!!
inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

   x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}

   x=\sqrt[3]{5^4} [Since, a^{\frac{1}{3}}=\sqrt[3]{a}]

   x=\sqrt[3]{5\times 5\times 5\times 5}

   Step 5:

   x=\sqrt[3]{(5)^3\times 5}

   x=\sqrt[3]{5^3}\times \sqrt[3]{5}

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

   (3x-1)^{\frac{1}{5}}=2

   Step 1:

   (3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}

   Step 2:

   (3x-1)=2^5

   Step 3:

   3x=32+1

   Step 4:

   x=11

4). By substituting x=11 in the original equation.

   (3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}

                         =(2^5)^\frac{1}{5}

                         =2

There is no extraneous solution.

3 0
3 years ago
The Girl Scouts are going to the pool it will cost him $2.50 per person to go and there are 10 people going
UkoKoshka [18]

Answer:

I would cost them $25.00 dollars

Step-by-step explanation:

This is Because if you do 2.50 x 10 = 25.00 or 25

4 0
3 years ago
Read 2 more answers
Can I have some help with this please.
pochemuha
Answer: 5

explanation:

4m-2=6
———
3

multiply 3 on both sides to cancel the 3 out

4m-2=18

add 2 from both sides to cancel the 2 out

4m=20

divide both sides by 4 to cancel out the 4
3 0
3 years ago
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Which of the following pairs of base and height produces the greatest area? All measurements are in centimeters.
egoroff_w [7]
B because 20 and 0.8 are the biggest
4 0
3 years ago
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