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HACTEHA [7]
3 years ago
5

If you were working with a quadratic equation

Mathematics
2 answers:
BabaBlast [244]3 years ago
8 0

(5x+6)2 is your answer

Genrish500 [490]3 years ago
5 0

Answer:

Step-by-step explanation:

y = 25x² + 60x + 36

= 25(x² + 2.4x) + 36

= 25(x² + 2.4x + 1.2²) - 25·1.2² + 36

= 25(x+1.2)² + 0

vertex (-1.2,0)

axis of symmetry x = -1.2

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If (5,-12) is a point on the terminal side of an angle θ, find the value of sin⁡θ, cos⁡θ, and tan⁡θ.
Bezzdna [24]

Answer:

Given point (5,-12) falls into IV quadrant

<u>The right triangle with legs of 5 and -12, and hypotenuse is:</u>

  • √5² + (-12)² = √25+144 = √169 = 13

<u>Value of sin⁡θ, cos⁡θ, and tan⁡θ:</u>

  • sin⁡ θ = -12/13
  • cos ⁡θ = 5/13
  • tan⁡ θ = -12/5

5 0
3 years ago
Planet X is 1/2 of a light-year away from Earth. Planet Y is 3/10 of a light-year away from Earth. How much farther away is Plan
kakasveta [241]

Answer:

1/2= 5/10

5/10 - 3/10 = 2/10 or 1/5

so planet X is 1/5 of a light-year closer

Step-by-step explanation:

8 0
3 years ago
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gladu [14]

Answer:

Step-by-step explanation:

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5 0
2 years ago
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37 is what percent of 144 to the nearest percent?
Misha Larkins [42]
37 is 26%(rounded up to the nearest percent) of 144
3 0
3 years ago
How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?
kakasveta [241]

This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.

Case 1: Five A's and One B

Total number of letters = 6

Total number of words possible = \frac{6!}{5!*1!}=6

Case 2: Five A's and Two B's

Total number of letters = 7

Total number of words possible = \frac{7!}{5!*2!}=21

Case 3: Five A's and Three B's

Total number of letters = 8

Total number of words possible = \frac{8!}{5!*3!}=56

Total number of possible words will be the sum of all three cases.

Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83

8 0
3 years ago
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